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Travka [436]
3 years ago
13

(0, 6) and (2, 96) in exponential function

Mathematics
1 answer:
Oxana [17]3 years ago
8 0

Answer:

If one of the data points has the form \displaystyle \left(0,a\right)(0,a), then a is the initial value. Using a, substitute the second point into the equation \displaystyle f\left(x\right)=a{\left(b\right)}^{x}f(x)=a(b)

​x

​​ , and solve for b.

If neither of the data points have the form \displaystyle \left(0,a\right)(0,a), substitute both points into two equations with the form \displaystyle f\left(x\right)=a{\left(b\right)}^{x}f(x)=a(b)

​x

​​ . Solve the resulting system of two equations in two unknowns to find a and b.

Using the a and b found in the steps above, write the exponential function in the form \displaystyle f\left(x\right)=a{\left(b\right)}^{x}f(x)=a(b)

​x

​​ .

Step-by-step explanation:

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100x2−36=4(5x+?)(5x−3)
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Answer:

?=3

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Pleasee help me .Use each digits 2,3,7,8 to make numbers FROM 20,21,22 SO ON ALL THE WAY TO 50 FOR EXAMPLE 2+3+7+8=20
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2,3,7,8=
1)3*7=21
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Hopes This Helps :)
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The table below shows a correct representation that 15 pounds (lb) of sugar cost $3:
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3 years ago
Help!!!!!!!!!!!!!!!!
Andru [333]

Step-by-step explanation:

The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:

let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9

let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9

let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9

let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9

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You can continue to increase the length of the square and follow this pattern and it will be consistent.

7 0
3 years ago
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