A student wants to restate some ideas she found in a journal article by a prominent expert in economics. She combines her own wo
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Answer:
The diameter of the shaft is 80.5 mm.
Explanation:
Torsion equation is applied for the diameter of the solid shaft.
Step1
Given:
Power of the shaft is 100 kw.
Revolution per minute is 160 RPM.
Allowable shear stress is 70 Mpa.
Maximum torque is 20% more than the mean torque.
Step2
Mean torque is calculated as follows:
T=5968.31 N-m
Step3
Maximum torque is calculated as follows:
T_{max}=7161.97 N-m
Step4
Apply torsional equation for diameter of shaft as follows:
d=0.0805 m
or,
d=80.5 mm
Thus, the diameter of the shaft is 80.5 mm.