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3 years ago

Technicians are normally paid in all of the following methods except:

Engineering

2 answers:

yawa3891 [41]3 years ago

7 0

Answer:

you didnt list the following methods

Explanation:

aksik [14]3 years ago

7 0

Answer: add your methods

Explanation:

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Sea water with a density of 1025 kg/m3 flows steadily through a pump at 0.21 m3 /s. The pump inlet is 0.25 m in diameter. At the

myrzilka [38]

Answer:

$\dot W_{pump} = 16264.922\,W\,(16.265\,kW)$

Explanation:

The pump is modelled after applying Principle of Energy Conservation, whose form is:

$\frac{P_{1}}{\rho\cdot g}+ \frac{v_{1}^{2}}{2\cdot g} +z_{1} + h_{pump}=\frac{P_{2}}{\rho\cdot g}+ \frac{v_{2}^{2}}{2\cdot g} +z_{2}$

The head associated with the pump is cleared:

$h_{pump} = \frac{P_{2}-P_{1}}{\rho\cdot g}+\frac{v_{2}^{2}-v_{1}^{2}}{2\cdot g}+(z_{2}-z_{1})$

Inlet and outlet velocities are found:

$v_{1} = \frac{0.21\,\frac{m^{3}}{s} }{\frac{\pi}{4}\cdot (0.25\,m)^{2} }$

$v_{1} \approx 4.278\,\frac{m}{s}$

$v_{2} = \frac{0.21\,\frac{m^{3}}{s} }{\frac{\pi}{4}\cdot (0.152\,m)^{2} }$

$v_{2} \approx 11.573\,\frac{m}{s}$

Now, the head associated with the pump is finally computed:

$h_{pump} = \frac{175\,kPa-81.326\,kPa}{(1025\,\frac{kg}{m^{3}} )\cdot (9.807\,\frac{m}{s^{2}} )} +\frac{(11.573\,\frac{m}{s} )^{2}-(4.278\,\frac{m}{s} )^{2}}{2\cdot (9.807\,\frac{m}{s^{2}} )} + 1.8\,m$

$h_{pump} = 7.705\,m$

The power that pump adds to the fluid is:

$\dot W_{pump} = \dot V \cdot \rho \cdot g \cdot h_{pump}$

$\dot W_{pump} = (0.21\,m^{3})\cdot (1025\,\frac{kg}{m^{3}})\cdot (9.807\,\frac{m}{s^{2}})\cdot(7.705\,m)$

$\dot W_{pump} = 16264.922\,W\,(16.265\,kW)$

4 0

3 years ago

Engine horsepower decreases ________% for every___________feet above sea level.

Nitella [24]

Answer:

Engine horsepower decreases 3.5% for every 1,000 feet above sea level.

4 0

3 years ago

If a cylindrical part with a length of 20 mm and a diameter of 20 mm is to be machined to a cylindrical part with 18 mm in diame

bulgar [2K]

Answer:

Titanium Alloy

Explanation:

Length ( L ) = 20 mm

D1 = 20 mm

d2 = 18 mm

l = 20 mm

Mechanical efficiency = 50%

power = 80 kW

cutting rake angle = 0°

cutting speed ( v ) = 10 m/s

Determine the material to be for the cylinder

In order to choose a material for the cylinder we have to calculate the cutting force

P = Fc * V

80 = Fc * 10 m/s

therefore Fc = 80 / 10 = 8 N

Hence the material we can use is Titanium Alloy due to low cutting force value

3 0

3 years ago

if you’re disassembling a master cylinder and the front piston assembly is stuck in the master cylinder you can

lianna [129]

Answer:

Put water in the cylinder then push the piston inward

Explanation:

When water is put it displaces all the air making it possible for the piston to be pulled easier and without distraction

6 0

3 years ago

ANIMAL SCIENCE NEED ASAP

miv72 [106K]

Answer:

i think its the last option

Explanation:

sorry its too late tho

8 0

3 years ago

Read 2 more answers