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3 years ago

Name 3 decimals whose product is about 40

1 answer:

7 0

<span>4/10 8/20 2/5 These fractions you then simplify and get a product of 40 hope this helps you figure the answer out quicker.</span>

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If you roll the six sided dice six times, are you guaranteed to get a sum of 7 once? answer

BlackZzzverrR [31]

Yes it can be guaranteed to get a sum of 7 once

5 0

3 years ago

Estimate the line of best fit using two points on the line 100 90 80 70 (e, 80) 60 30 20 10 (2.20) 10 O A. y= 2x O B. y = 2x+10

nexus9112 [7]

Answer:

$y = 10x$

Step-by-step explanation:

Given

The attached plot

Required

The line of the best fit using $(8,80)$ and $(2,20)$

We have:

$(x_1,y_1) = (8,80)$

$(x_2,y_2) = (2,20)$

Calculate slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{20 - 80}{2- 8}$

$m = \frac{-60}{-6}$

$m = 10$

The equation is then calculated using:

$y = m(x - x_1) + y_1$

$y = 10(x - 8) + 80$

Expand

$y = 10x - 80 + 80$

$y = 10x$

5 0

3 years ago

What are the parallel lines and the perpendicular lines

djyliett [7]

Parallel is MN and QP and perpendicular is MQ and OP

4 0

3 years ago

If k is a positive integer and n = k(k + 7), is n divisible by 6 ? (1) k is odd. (2) When k is divided by 3, the remainder is 2.

olganol [36]

Answer:

1.) Yes

2.) Yes

Step-by-step explanation:

Given that

n = k(k + 7)

If k is a positive integer and n = k(k + 7), is n divisible by 6 ?

(1) k is odd. Yes.

Let assume that k = 3

Then, n = 3(3 + 7)

n = 3 × 10

n = 30.

30 is divisible by 6.

(2) When k is divided by 3, the remainder is 2. That is,

Let k = 5

Then,

5/3 = 1 remainder 2

Substitute k into the equation

n = k(k + 7)

n = 5(5 + 7)

n = 5 × 12

n = 60

And 60 is divisible by 6.

Therefore, the answer to both questions is Yes.

5 0

3 years ago

Convert the complex number z = 4 - 10i from rectangular form to polar form.

mrs_skeptik [129]

ANSWER

$r = 2 \sqrt{29} ( \cos(292 \degree) + \sin(292 \degree))$

EXPLANATION

The polar form of a complex number ,

$z = x + yi$

is given by:

$z = r( \cos( \theta) + i \sin( \theta) )$

where

$r = \sqrt{ {x}^{2} + {y}^{2} }$

The given complex number is:

$z = 4 - 10i$

$r = \sqrt{ {4}^{2} + {( - 10)}^{2} }$

$r = \sqrt{16 + 100}$

$r = \sqrt{116} = 2 \sqrt{29}$

And

$\theta= \tan^{ - 1}(\frac{ y}{x} )$

$\theta= \tan^{ - 1}(\frac{ - 10}{4} )$

$\theta= 292 \degree$

Hence the polar form is :

$r = 2 \sqrt{29} ( \cos(292 \degree) + \sin(292 \degree))$

6 0

3 years ago