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dimulka [17.4K]

3 years ago

11

What is the volume of a square based pyramid with a side 11 cm and a perpendicular height of 20 cm

1 answer:

Kaylis [27]3 years ago

3 0

V=lw*h/3

So since its a square l and w are the same

11*11 = 121

h=20

20/3= 6.6666666

V=121*6.6666666

V= 806.66667

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Write each expression in simplified radical form PLEASE HELP ITS DUE FRIDAY AND I DONT UNDERSTAND THIS AT ALL REALLY BAD TEACHER

Nonamiya [84]

Answer:

1) The simplified radical form is $\sqrt{36x^2}=6x$

2) The simplified radical form is $\sqrt{72x^3}=6x\sqrt{2x}$

3) The simplified radical form is $\sqrt{15x^8}=\sqrt{15}x^4$

4) The simplified radical form is $\sqrt{36x^7}=6x^3\sqrt{x}$

Step-by-step explanation:

1) Given expression is $\sqrt{36x^2}$

To find the simplified radical form of the given expression :

$\sqrt{36x^2}$

$=\sqrt{36\times x^2}$

$=\sqrt{36}\times \sqrt{x^2}$

$=\sqrt{6\times 6}\times \sqrt{x\times x}$

$=6\times x$

$\sqrt{36x^2}=6x$

Therefore the simplified radical form is $\sqrt{36x^2}=6x$

2)Given expression is $\sqrt{72x^3}$

To find the simplified radical form of the given expression :

$\sqrt{72x^3}$

$=\sqrt{72\times x^3}$

$=\sqrt{72}\times \sqrt{x^3}$

$=\sqrt{9\times 8}\times \sqrt{x\times x\times x}$

$=\sqrt{9}\times \sqrt{8}\times x\sqrt{x}$

$=3\times 2\sqrt{2}\times x\sqrt{x}$

$\sqrt{72x^3}=6x\sqrt{2x}$

Therefore the simplified radical form is $\sqrt{72x^3}=6x\sqrt{2x}$

3) Given expression is $\sqrt{15x^8}$

To find the simplified radical form of the given expression :

$\sqrt{15x^8}$

$=\sqrt{15\times x^8}$

$=\sqrt{15}\times \sqrt{x^8}$

$=\sqrt{5\times 3}\times \sqrt{x^4\times x^4}$

$=\sqrt{15}\times x^4$

$\sqrt{15x^8}=\sqrt{15}x^4$

Therefore the simplified radical form is $\sqrt{15x^8}=\sqrt{15}x^4$

4) Given expression is $\sqrt{36x^7}$

To find the simplified radical form of the given expression :

$\sqrt{36x^7}$

$=\sqrt{36\times x^7}$

$=\sqrt{36}\times \sqrt{x^7}$

$=\sqrt{6\times 6}\times \sqrt{x^3\times x^3\times x}$

$=6\times x^3\sqrt{x}$

$\sqrt{36x^7}=6x^3\sqrt{x}$

Therefore the simplified radical form is $\sqrt{36x^7}=6x^3\sqrt{x}$

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3 years ago