When a die is rolled 20 times, 4 came up 5 times.

<img src="https://tex.z-dn.net/?f=%5Clim_%7Bx%5Cto%20%5C%200%7D%20%5Cfrac%7B%5Csqrt%7Bcos2x%7D-%5Csqrt%5B3%5D%7Bcos3x%7D%20%7D%7

salantis [7]

Answer:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

L'Hopital's Rule

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

We are given the limit:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}$

When we directly plug in x = 0, we see that we would have an indeterminate form:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}$

This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:

$\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}$

Plugging in x = 0 again, we would get:

$\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}$

Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:

$\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}$

Substitute in x = 0 once more:

$\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}$

And we have our final answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

6 0

3 years ago

What is the measure of 4?

zlopas [31]

Answer:

∠ 4 = 80°

Step-by-step explanation:

∠ 5 and 100° are vertical angles and are congruent , so

∠ 5 = 100°

∠ 4 and ∠ 5 are same- side interior angles and sum to 180° , that is

∠ 4 + ∠ 5 = 180°

∠ 4 + 100° = 180° ( subtract 100° from both sides )

∠ 4 = 80°

8 0

2 years ago

The circumference of a circular field is 285.5 yards. What is the diameter of the field? Use 3.14 for pi and do not round your a

ArbitrLikvidat [17]

Hi hope this helps, thanks

6 0

3 years ago

Read 2 more answers

Write the time for each one. Translate to English

satela [25.4K]

9. 9:15
10. 1:30
11. 2:15
12. 7:30
13. 10:15
14. 5:40
15. 9:05
16. 2:05

i just finished learning this myself :)

7 0

3 years ago

Solve Systems Graphically and graphs pls solve 2 of them at least and three to get brainliest!

rewona [7]

Answer:

43b. (-1, 2)

43a. (1, -3)

36b. Yes: (0,9)

Step-by-step explanation:

43b. x+y=1

-x+y=3

----------------------

2y=4 > y=2

2+x=1 > x=-1

check:

2(-1)+2=0

0=0

43a. can you figure this one out by yourself and then check it? If you can't I will show my work. The answer is above. :)

36b. y-(0)^2=9

y=9

3 0

3 years ago