Answer:
257/1000
Step-by-step explanation:
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Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
For this case, what you must do is take out the area of two triangles and add it to the area of a rectangle to find the total area.
We have then:
Triangle area:
A = (1/2) * ((13-9) / (2)) * (10) = 10 in ^ 2
Rectangle area:
A = (9) * (10) = 90 in ^ 2
Total area:
At = 2 * (10) + 90 = 110 in ^ 2
answer:
110 in²
Answer:
2.5 minutes per quesiton
Step-by-step explanation:
75 minutes to take 30 quesitons means you divide the time equally so
75/30
First term (a) = -15
common difference(d)= -9-(-15)
= -9+15=6
So,
12th term(a12)= a +(n-1)d
= -15+(12-1)×6
= -15 + 11×6
= -15+66
= 51
