Answer:
The value is
Explanation:
From the question we are told that
The amount of force a square meter of an aircraft wing should produce is
The air speed relative to the bottom of the wing is
The air level density of air is
Gnerally this force per square meter of an aircraft wing is mathematically represented as
Here u is the speed air need to go over the top surface to create the ideal lift
A is the area of a square meter i.e
So
=>
During the period of constant acceleration, the car's average speed is (1/2) (16 + 32) = 24 m/s.
At that average speed, it covers 240 meters in 10 seconds.
Answer:
Assuming air resistance is negligible, all of the potential energy that the object has at the top of the ramp is converted into kinetic energy by the time it gets to the bottom of the ramp. This is because no matter what path the object takes to move the 5m vertically (ie. falling straight down v. sliding on the ramp), gravity does the same amount of work on it.
Thus, calculate the total amount of potential energy at the top of the ramp:
Ep=mgh
Ep=4(9.81)5
Ep=196.2 Joules
Because all of this potential energy is converted into kinetic energy in the object by the bottom of the ramp, the object hits the spring with 196.2J of energy.
By using the formula for elastic potential energy, you can calculate exactly how far the spring compresses.
196.2=(1/2)k(x^2)
392.4=(350)(x^2)
1.1211=x^2
sqrt(1.1211)=x
x=1.059m
As for the last part of the question, after the object compresses the spring fully and stops momentarily, the spring converts it's elastic potential energy back into kinetic energy in the object and pushes it away again.
Explanation:
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