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romanna [79]
3 years ago
5

The orbits of all the planets in the solar system are slightly elliptical with the exception of _______.

Physics
1 answer:
aksik [14]3 years ago
5 0

Answer:

There is no exception to this. all planets have some eccentricity. it is physically impossible to have an orbit without any eccentricity. However, venus's orbit has the lowest (0.007) eccentricity (closest to circular) so that could be your answer.

Mercury's orbit's eccentricity 0.2

Venus's orbit's eccentricity 0.007 (this is the lowest so it may be your answer)

Earth's orbit's eccentricity 0.0167

Mars's orbit's eccentricity 0.0934

Jupiter's orbit's eccentricity 0.0489

Saturn's orbit's eccentricity 0.0565

Neptune's orbit's eccentricity 0.009

Uranus's (yur,in,iss) orbit's eccentricity 0.0457

Pluto's (not really a planet) orbit's eccentricity 0.2444 (very high)

hope it helped.

Wbob3914

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Explanation:

Lets state the parameters we are being given right from the question:

Number of rectangular coil, (N) = 44

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Width of Coil, w =8.10cm in meters we have; (w) = 8.10 × 10⁻² m

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Angular Speed of Coil, (ω) = 64 rad/s

(a)

To calculate the induced emf in the rotating cell,we can use the formula:

emf = NBAωsin(ωt)

For maximum induced emf, the value of sin(ωt) will be 1

emf_max = NBAω ; if (A = l × w) , we have:

emf_max  = NB(l × w)ω

subsitituting the parameters into the above equation; we have:

emf_max  = 44 × 765 × 10⁻³ ( 17 × 10⁻² × 8.10 × 10⁻² ) × 64

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(b)

At t = 1s, the induced emf is calculated as:

emf = NBAωsin(ωt)

substituting the parameters into the equation, we have:

emf =   44 × 765 × 10⁻³ ( 17 × 10⁻² × 8.10 × 10⁻² ) × 64 × sin (64 × 1)

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To calculate the maximum rate of change of the magnetic flux through the rotating coil; we need to reflect on the equation for the maximum induced emf in terms of magnetic flux.

i.e emf_max = N\frac{d∅}{dt}

since emf_max = 29.66 and N = 44; we have:

29.66 =  44\frac{d∅}{dt}

\frac{d∅}{dt} = \frac{29.66}{44}

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