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seropon [69]
3 years ago
13

In an LC circuit containing a 40-mH ideal inductor and a 1.2-mF capacitor, the maximum charge on the capacitor is 45mC during os

cillations. What is the maximum current through the inductor during the oscillations?
A) 3.7 A
B) 42 A
C) 2.5 A
D) 10 A
E) 6.5 A
Physics
1 answer:
GalinKa [24]3 years ago
3 0

Answer:

E) 6.5 A

Explanation:

Given that

L = 40 m H

C= 1.2 m F

Maximum charge on capacitor ,Q= 45 m C

The maximum current I given as

I = Q.ω

ω =angular frequency

\omega=\dfrac{1}{\sqrt{CL}}

By putting the values

\omega=\dfrac{1}{\sqrt{CL}}

\omega=\dfrac{1}{\sqrt{40\times 10^{-3}\times 1.2 \times 10^{-3}}}

ω  = 144.33 rad⁻¹

Maximum current

I = 45 x 10⁻³ x 144.33  A

I= 6.49 A

I = 6.5 A

E) 6.5 A

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Two horses on opposite sides of a narrow stream are pulling a barge up the stream. Each hors pulls with a force of 720N. The rop
Sonja [21]
For the answer to the question above, each horse's force forms a right angle triangle with the barge and subtends an angle of 60/2 = 30°. The resultant in the direction of the barge's motion is:
Fx = Fcos(∅)
We can multiply this by 2 to find the resultant of both horses.
Fx = 2Fcos(∅)
Fx = 2 x 720cos(30)
Fx = 1247 N
8 0
3 years ago
A spaceship with a constant speed of 0. 800c relative to earth travels to a star that is 4. 30 light-years from earth. how much
Strike441 [17]

Main Answer:

Given  speed of spaceship v = 0.8c = 0.8 * 3 x 10^8 m/s

Speed of spaceship v = 2.4 x 10^8 m/s

Distance need to be travelled d = 4.3 light years

we know that 1 light year  = 9.461 x 10^15 m

Distance need to be travelled d = 4.3 x 9.461 x 10^15

d = 40.6823 x 10^15 m

Time taken for the trip would elapse on a clock on board the spaceship

t = distance/ velocity

t = 40.6823 x 10^15 / 2.4 x 10^8

t = 16.95 x 10^7 sec

t = 4.71 x 10^4 hours

Explanation:

What is light year?

Light year is defined as the distance travelled by the light in one year. In a year, light travels through 300000 km per sec in the interstellar space.

To know more about spaceship, please visit: brainly.com/question/14423386

#SPJ4

3 0
1 year ago
True or False<br><br> If the wavelength of a wave increases, its frequency also increases.
Degger [83]
False, when wavelength waves increases the frequency will decreases. 
5 0
2 years ago
Two tuning forks A and B when sounded together produce 5 beats per second. The tuning fork A has frequency 480Hz. The fork B is
BartSMP [9]
<h2>The frequency of tuning fork B is 475 Hz</h2>

Explanation:

The number of beats produced is equal to the frequency difference between the two tuning forks .

The frequency of A = 480 Hz

Thus the frequency of B can be = 485 or 475 Hz

When B is filed , its frequency increases and it start producing 2 beats with A .

Thus it frequency must be 475 Hz , by filing , it increases to 478 Hz .

By which it gives  480 - 478 = 2 beats per second .

This cannot happen with frequency 485 , because by filing this difference increases in place of decreasing .

5 0
3 years ago
Two charges that are separated by one meter exert 1-N forces on each other. If the charges are pushed together so the separation
Nana76 [90]

Answer: 16N

Explanation:

According to coulombs law which states that the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically,

F = kq1q2/r²

If two charges that are separated by one meter exert 1-N forces on each other, the equation will become

1 = kq1q2/1²

kq1q2 = 1 ... (1)

If the charges are pushed together so the separation is 25 centimeters, the force between them becomes,

F = kq1q2/0.25² (25cm converted to meters)

0.0625F = kq1q2 ... (2)

Dividing equation 1 by 2 to determine the force F on each charges, it becomes;

1/0.0625F = kq1q2/kq1q2

1/0.0625F = 1

0.0625F = 1

F = 1/0.0625

F= 16N

6 0
3 years ago
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