If f(x)=1/9x-2
then f^-1(x) will be
lets assume f(x)=y
y=1/9x-2
y+2=1/9x
9(y+2)=x
f^-1(x)=9(y+2)
rest u can do with the same method
If you're looking for an angle in between those, basically you have to choose an angle between 0 and 90°. any angle should work (such as 15°, 45°, 60°, 75°, etc.)
Angles XQL and MQR are congruent because they are vertical angles. So
209 - 13 <em>b</em> = 146 - 4 <em>b</em>
Solve for <em>b</em> :
209 - 13 <em>b</em> = 146 - 4 <em>b</em>
209 - 146 = 13 <em>b</em> - 4<em> b</em>
63 = 9 <em>b</em>
<em>b</em> = 63/9 = 7
Then the measure of angle XQL is
(209 - 13*7)º = 118º
Answer:
t = 9.57
Step-by-step explanation:
We can use trig functions to solve for the t
Recall the 3 main trig ratios
Sin = opposite / hypotenuse
Cos = adjacent / hypotenuse
Tan = opposite / adjacent.
( note hypotenuse = longest side , opposite = side opposite of angle and adjacent = other side )
We are given an angle as well as its opposite side length ( which has a measure of 18 ) and we need to find its adjacent "t"
When dealing with the opposite and adjacent we use trig ratio tan.
Tan = opp / adj
angle measure = 62 , opposite side length = 18 and adjacent = t
Tan(62) = 18/t
we now solve for t
Tan(62) = 18/t
multiply both sides by t
Tan(62)t = 18
divide both sides by tan(62)
t = 18/tan(62)
t = 9.57
And we are done!
Answer:
it's a parallelogram
Step-by-step explanation:
May ot helpful