Dipole-dipole interactions occur when the partial charges formed within one molecule are attracted to an opposite partial charge in a nearby molecule. Polar molecules align so that the positive end of one molecule interacts with the negative end of another molecule.
So the answer is, D.) dipole to dipole.
Answer:
30.34g (corrected to 4 significant figures).
Explanation:
Take the atomic mass of C=12.0, H=1.0, O=16.0.
no. of moles = mass / molar mass
So, no. of moles of butane reacted = 10 / (12x4 + 1x10)
= 0.172414 mol
Since O2 is in excess and butane is the limiting reagent, the no. of moles of carbon dioxide produced depends on the no. of moles of butane reacted.
From the equation, the mole ratio of butane:Carbon dioxide = 2: 8 = 1: 4,
meaning 1 mole of butane gives 4 moles of CO2.
Using this ratio,
we can deduce that the no. of moles of CO2 produced = 0.172414 x 4
=0.689655 mol
As mass = no. of moles x molar mass
mass of CO2 produced = 0.689655 x (12.0+16.0x2)
=30.34g (corrected to 4 significant figures).
Answer:
The correct option is: B. 13g
Explanation:
Given: Molar mass of iron (II) sulfate: m = 260g/mol,
Molarity of iron (II) sulfate solution: M = 0.1 M,
Volume of iron (II) sulfate solution: V = 500 mL = 500 × 10⁻³ = 0.5 L (∵ 1L = 1000mL)
Mass of iron (II) sulfate taken: w = ? g
<em>Molarity</em>:
Here, n- total number of moles of solute, w - given mass of solute, m- molar mass of solute, V- total volume of solution in L
∴ <em>Molarity of iron (II) sulfate solution:</em>
⇒
⇒
⇒ <em>mass of iron (II) sulfate taken:</em>
<u>Therefore, the mass of iron (II) sulfate taken for preparing the given solution is 13 g.</u>
Answer:
Explanation:
mass of the solution = volume x density = 200 x 1 = 200 gm
heat absorbed = m x s x Δ t , s is specific heat , Δt is rise in temperature
= 200 x 4.18 x ( 31.3 - 24.6 )
= 5601 J .
This is the enthalpy change required.