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2 years ago

HOW MANY MOLES ARE IN 2.6 X 1024 ATOMS OF SILICON?

Chemistry

1 answer:

V125BC [204]2 years ago

8 0

Answer:

Let x moles of silicon contains 2.8x10^24 atoms. 6.02x10^23 atoms are present in 1 mole of Si. Therefore 2.80x10^24 atoms are present in = 2.8x10^24/6.02x10^23 = 4.65 moles of Si.

Explanation:

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Draw the products formed from 2-methyl-2-butene by sequences (1.) and (2.). hydroboration followed by oxidation with alkaline hy

nata0808 [166]

Answer:

product won't form hydrogen bond with water

Explanation:

6 0

3 years ago

A. The half-life for a first order reaction in 49 minutes. What is the rate constant?B.For a second order reaction, the half-lif

Burka [1]

Answer:

a) 0,014 min⁻¹

b) 1452 seconds.

c) 0,02156 M

d) The faster rate is for the reaction A. The largest rate constant, k, is for A reaction

Explanation:

a) For a first order reaction the half-life is:

$t_{1/2} = \frac{ln(2)}{k}$ (1) As half.life is 49 min. Rate constant -k- is: 0,014 min⁻¹

b) The half-life is defined as the time that takes in descompose the half of the initial concentration of a compound.

As half-life is 726s. In 726s the concentration will be 0,300M, In the next 726s the concentration will be 0,150M. Thus, thae time it takes to decrease concentration until 0,150M is 726s×2= 1452 seconds

c) In the same way, 11072 years are 4 half-life for this reaction, thus:

0,345M/2⁴ = 0,02156 M

d) By definition of half-life, the less half-life, the faster rate. Thus, The faster rate is for the reaction A.

By (1) half-life is inversely proportional to rate constant. Thus, the less half-life, the largest rate constant. The largest rate constant, k, is for A reaction

I hope it helps!

7 0

3 years ago

During which process does an atom gain one or more electrons?

valentinak56 [21]

oxidation i say 33333333333333333333333

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3 years ago

Which solution is more concentrated?

deff fn [24]

2 moles of NaOH dissolved in 1 litre of solution is the solution with more concentration.

Answer: Option A

Explanation:

Concentration of solution is the measure of the amount of solute dissolved in the solvent of the solution. So this is measured using the molarity of the solution. Molarity is determined as the number of moles of the solute present in the given amount of solvent.

$\text {Molarity}=\frac{\text {Moles of solute}}{\text {Amount of solvent }}$

In this present case, the option A gives the molarity of 2 M as

$\text {Molarity}=\frac{2}{1}=2 M$

But the second option, mass of NaOH is given. So we have to determine the molarity. First we have to find the molar mass of NaOH. We know that 1 mole of NaOH will contain 40 g/mole.

1 g of NaOH = 40 g of NaOH

1 g of NaOH = 1/40 moles

So 2 g of NaOH will contain $\frac{2 g}{40 g/mole}$ which is equal to 0.05 moles of NaOH.