Answer:
EVAPORATES IN THE PROCESS OF TRANSPIRATION
Explanation:
Plants takes in water from the soul via it's root system. Small amount of the water are used for growth and metabolism of the plants. Some are used in the process of photosynthesis. The bulk of the remaining are lost through transpiration. This takes place in the stomata of the plants. The stomata are numerous on the leaf surfaces and are guarded by cells which allow for opening and closing of the stomata. Transpiration helps the plants to remove CO2 produced by photosynthesis, cools the plant and also changes osmotic pressure of the plant which allows for the flow of nutrients and water from the root to the leaves, flowers, fruits.
Answer:
D. The volume of the solvent used was less than 5 liters.
Explanation:
- We have the rule: the no. of moles before dilution equal the no. of moles after dilution.
<em>(MV) before dilution = (MV) after dilution.</em>
M before dilution = 10.0 M, V before dilution = V of stock = ??? L.
M after dilution = 1.0 M, V after dilution = 5.0 L.
<em>V before dilution = V of stock = (MV) after dilution/M before dilution</em> = (1.0 M)(5.0 L)/(10.0 M) = <em>0.5 L.</em>
∴ The volume of the stock used is 0.5 L.
The volume of the solvent used is 4.5 L.
<em>D. The volume of the solvent used was less than 5 liters.</em>
Answer:
16.89g of PbBr2
Explanation:
First, let us calculate the number of mole of Pb(NO3)2. This is illustrated below:
Molarity of Pb(NO3)2 = 0.595M
Volume = 77mL = 77/1000 = 0.077L
Mole =?
Molarity = mole/Volume
Mole = Molarity x Volume
Mole of Pb(NO3)2 = 0.595x0.077
Mole of Pb(NO3)2 = 0.046mol
Convert 0.046mol of Pb(NO3)2 to grams as shown below:
Molar Mass of Pb(NO3)2 =
207 + 2[ 14 + (16x3)]
= 207 + 2[14 + 48]
= 207 + 2[62] = 207 +124 = 331g/mol
Mass of Pb(NO3)2 = number of mole x molar Mass = 0.046 x 331 = 15.23g
Molar Mass of PbBr2 = 207 + (2x80) = 207 + 160 = 367g/mol
Equation for the reaction is given below:
Pb(NO3)2 + CuBr2 —> PbBr2 + Cu(NO3)2
From the equation above,
331g of Pb(NO3)2 precipitated 367g of PbBr2
Therefore, 15.23g of Pb(NO3)2 will precipitate = (15.23x367)/331 = 16.89g of PbBr2
Answer:
in first picture pressure is low and in second picture the pressure is high
2ans in first picture air is
less amount
in second picture air is high amount
