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kvv77 [185]
3 years ago
14

Write a balanced nuclear equation for the following: The nuclide astatine-218 undergoes alpha emission to give bismuth-214

Chemistry
1 answer:
galina1969 [7]3 years ago
7 0

Answer:

^{218}_{85}At\rightarrow ^{214}_{83}Bi+^{4}_{2}He

Explanation:

Hello there!

In this case, since the radioactive reaction for the alpha emission of astatine-218 to bismith-214 involve the release of a helium atom as shown below:

^{218}_{85}At\rightarrow ^{214}_{83}Bi+^{4}_{2}He

Whereas the atomic number decreases by 2 and the mass number by 4 in agreement to the release of the Helium atom.

Regards!

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Explanation:

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What are the names of the positive and negative electrodes of an electrolytic cell?
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2 years ago
6.9 moles of oxygen gas in a fixed volume of 1.33 liters. One of the valves opened and there remains only 1.24 moles oxygen gas.
Romashka [77]

Answer:

The new volume of the gas remains the same. That is new volume of gas is 1.33 litres

Explanation:

This is because gases do not have a definite shape. They therefore take the shape of their containing vessels and hence their volumes are determined by the volume of the container.

For the question above even if some of the gas escapes, as long as there is gas present in the container, its volume remains the same, that is occupies the same space in the container

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A sample of carbon dioxide at RTP is 0.50 dm3. How many grams of carbon dioxide do we have?
prohojiy [21]

Answer:

0.924 g

Explanation:

The following data were obtained from the question:

Volume of CO2 at RTP = 0.50 dm³

Mass of CO2 =?

Next, we shall determine the number of mole of CO2 that occupied 0.50 dm³ at RTP (room temperature and pressure). This can be obtained as follow:

1 mole of gas = 24 dm³ at RTP

Thus,

1 mole of CO2 occupies 24 dm³ at RTP.

Therefore, Xmol of CO2 will occupy 0.50 dm³ at RTP i.e

Xmol of CO2 = 0.5 /24

Xmol of CO2 = 0.021 mole

Thus, 0.021 mole of CO2 occupied 0.5 dm³ at RTP.

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