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blondinia [14]
3 years ago
7

Use elimination to solve and match each system of equations to the correct solution.

Mathematics
1 answer:
podryga [215]3 years ago
7 0

\begin{cases}2x-9y=-51\\2x-3y=-9\end{cases}\\\\\\\begin{cases}(2x-9y)(-1)=-51(-1)\\2x-3y=-9\end{cases}

\begin{cases}-2x+9y=51\\2x-3y=-9\end{cases}     (adding the second equation to the first one)

\begin{cases}\qquad6y=42\\2x-3y=-9\end{cases}\\\\\\\begin{cases}\qquad y=7\\2x-3y=-9\end{cases}\\\\\\\begin{cases}y=7\\2x-3(7)=-9\end{cases}\\\\\\\begin{cases}y=7\\2x-21=-9\end{cases}\\\\\\\begin{cases}y=7\\2x=12\end{cases}\\\\\\\begin{cases}x=6\\y=7\end{cases}

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PLEASE HELP ME WITH THIS PROBLEM!!!!!!
Jet001 [13]

Answer:

n = 59

Step-by-step explanation:

I find it easiest to work problems of this kind using a graphing calculator. That way, extraneous solutions can be avoided. It seems to work well to rewrite the problem, so you're looking for a value of n that makes the result zero. Here, that would mean you want ...

... f(n) = √(n+5) -√(n-10) -1

_____

The solution by hand involves eliminating the root symbols. You do that by squaring the equation:

... n +5 -2√((n+5)(n-10)) + n -10 = 1

Now, we isolate the remaining root and square again.

... 2n -6 = 2√((n+5)(n-10)) . . . collect terms, add 2√( ) -1

... n -3 = √(n²-5n-50) . . . . . . . divide by 2

... n² -6n +9 = n² -5n -50 . . . . square both sides

... 59 = n . . . . . . . . . . . . . . . . . add 50 +6n -n²

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3 years ago
What is the volume of a cylinder with a height of 4xy^4 and a radius of 2x? (The formula fo
OLga [1]

Answer:

volume: \sf 16\pi x^3y^4

given:

  • height: \sf 4xy^4
  • radius: \sf 2x

<u>cylinder volume</u>:

\hookrightarrow \sf \pi r^2h

\hookrightarrow  \sf \pi (2x)^2(4xy^4)

\hookrightarrow  \sf \pi (4x^2)(4xy^4)

\hookrightarrow  \sf 16\pi x^3y^4

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2 years ago
Write an expression for cotA
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Answer:

cotA=\frac{2x}{5}

Step-by-step explanation:

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1 year ago
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thanks me later, pa brainliest po ako
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2 years ago
The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.​
erma4kov [3.2K]

Answer:

  • CSA of the cylinder = 440 sq. cm

  • Volume of the cylinder = 1540 cu. cm

\\

Step-by-step explanation:

Given:

  • Radius of the cylinder = 7 cm
  • Height of the cylinder = 10 cm

\\

To Find:

  • Curved surface area
  • Volume

\\

Solution:

\\

Using formula:

\dashrightarrow \:  \:  { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA  \: of  \: cylinder = 2\pi rh}}}}}}  \:  \star \\  \\

<em>Substituting the required values: </em>

\\

\dashrightarrow \:  \:  \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times  10 \\  \\  \\  \dashrightarrow \:  \:  \sf CSA {(cylinder)}  = 2 \times 22 \times 10 \\  \\ \\   \dashrightarrow \:  \:  \sf CSA {(cylinder)} = 44 \times 10 \\  \\  \\  \dashrightarrow \:  \:  \sf CSA {(cylinder)}  = 440 \:  {cm}^{2}  \\ \\ \\

Now,

\dashrightarrow \:  \:  { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}=  \pi {r}^{2} h}}}}}}  \:  \star \\  \\ \\

<em>Substituting the required values, </em>

\\

\dashrightarrow \:  \:   \sf Volume {(cylinder)}=  \dfrac{22}{7}  \times  {(7)}^{2}  \times 10 \\ \\  \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}=  \frac{22}{7}  \times 49  \times 10 \\ \\ \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\  \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}= 1540 {cm}^{3}  \\ \\ \\

Hence,

  • CSA of the cylinder = 440 sq. cm

  • Volume of the cylinder = 1540 cu. cm
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