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3 years ago

In how many ways can four people sit next to each other in a movie theater row?

2 answers:

6 0

As far as we can tell is just a Permutation

how many ways to arrange 4 out of 4, where order matters,

$\bf _nP_r=\cfrac{n!}{(n-r)!}\qquad \qquad \qquad \qquad _4P_4=\cfrac{4!}{(4-4)!}\implies \cfrac{4!}{1}$

Gnoma [55]3 years ago

4 0

2 of the them have to seat in the front row and the two others in the back

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Can someone answer each step of this correctly?

Burka [1]

About Slope - Intercept Form:

y = mx + b
m is the slope
b is the y-intercept

About Standard Form:

Ax + By = C
A & B & C are integers
A & B are both non-zero
This form is good to use when wanting to find the x & y intercepts of a line

About Point - Slope Form:

Y - Y1 = m (x -X1)
Y1 & X1 is a point on the line
The form allows you to identify the slope & the point on the line

Other Info:

Remember, y comes before the x
An ordered pair from your problem: (-3,1), -3 is x & 1 is y & x is before the y
An ordered pair from your problem: (3,5), 3 is x & 5 is y & x is before the y
For the graph, the vertical line is y

For the graph, the horizontal line is x

Hope this information helps!!! :)

5 0

3 years ago

An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$

Therefore, the debris will reach a height of 56 ft twice.

When time $t=0.5\ s$ during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at $t=7\ s$ , the height is 56 ft.

5 0

3 years ago

Which of the following statements are true?

astraxan [27]

C I think the answer is

8 0

3 years ago

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Joe played the trumpet from 6:30 to 7:05 one day. The next he played from 3:55 to 4:15. How many minutes did he play in two days

VARVARA [1.3K]

Answer:

55 minutes

Step-by-step explanation:

7 0

3 years ago

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43 ones times 3 tens = how many tens

romanna [79]

Well 43 ones times 3 tens is basically 43 times 30 which is 1,290
then divide that by ten to get how many tens and you will get 129 tens
hope this helps

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3 years ago

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