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Oksi-84 [34.3K]
3 years ago
11

The cost of an item is 100% of its price. What number goes in place of ? in the addition problem?

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
8 0
I believe this is the complete problem. 

<span>Anton bought a picnic cooler. His total bill, with tax, was $7.95. He paid 6 percent sales tax. How much did he pay for the cooler alone without the tax? The cost of an item is 100% of its price. What number goes in place of ? in the addition problem?
</span>
The answer is the below:

<span>He paid $7.473 without tax because $7.95 x 96% or (0.96) =$7.473</span>
borishaifa [10]3 years ago
6 0

Answer:

The value of x is $7.5

Step-by-step explanation:

Given The cost of an item is 100% of its price.

Anton bought a picnic cooler. The total bill, with the tax, was $7.95. He paid 6% sales tax.

we have to tell how much he pay for cooler without tax.

We have to find the value of ? let it be x shown in expression.

By the given expression we can write

x+6% of x=$7.95

⇒ x(1+0.06)=$7.95

⇒ 1.06x=7.95 ⇒ x=7.5

Hence, the value of x is $7.5

He paid $7.5 without taxes.

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Step-by-step explanation:

Given

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<em>See attachment for complete question</em>

Required

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522 divide by 58 is 9

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4 years ago
The germination rate is the rate at which plants begin to grow after the seed is planted.
chubhunter [2.5K]

Answer:

z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

\hat p=\frac{7}{15}=0.467 estimated proportion of seeds germinated

p_o=0.9 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:  

Null hypothesis:p\geq 0.9  

Alternative hypothesis:p < 0.9  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

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