The answer is c to your question
A) m=months passed
f(m)=2*1.05^m
b) 8 weeks=2 months
f(2)=2*1.05^2=2.205
so essentially still 2
c)100=2*1.05^m
50=1.05^m
log1.05(50)=m
log(50)/log(1.05)=m=80.18
so after 80 months she will have nearly 100 cats (99.12), but will only break through the 100 with her 81st month
Answer:
= 1
Step-by-step explanation:
The demand for that college will be equal to 1 or it can be said as unit elastic demand over the tuition range. This means that the demand for the college would move proportionately with the tuition range of that college, since the change in revenue is due to the change in tuition only.
Hope this helps.
Good luck and cheers.
Answer:
the first and last answer, 1 and 4
Step-by-step explanation: