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Dennis_Churaev [7]
4 years ago
9

What is the volume of the right rectangular prism with a length of 2 millimeters, a width of 4 millimeters, and a height of 8 mi

llimeters? 14 Millimeters cubed 16 Millimeters cubed 28 Millimeters cubed 64 Millimeters cubed
Mathematics
2 answers:
Mademuasel [1]4 years ago
8 0

Answer:

The volume of this prism is 64 mililmeters cubed.

Step-by-step explanation:

What is the volume of the right rectangular prism with a length of 2 millimeters, a width of 4 millimeters, and a height of 8 millimeters?

The volume of this prism can be calculated as:

V=l\cdot w \cdot h\\\\V=2\cdot 4\cdot 8=64

The volume of this prism is 64 mililmeters cubed.

pantera1 [17]4 years ago
8 0

Answer:

D

Step-by-step explanation:

Sorry if it's wrong.

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Please help me with this, thanks guys
tangare [24]

Answer:

1) 1 | 3, 5, 8

2| 2, 4, 6, 6

3| 4, 8, 9

4| 5, 5

5| 1, 5, 6

Step-by-step explanation:

You put the tens place in the "stem" section and the ones in the "leaf" section. For 3 digit number you but both the hundreds and tens in the stem spot. Ex) 23 | 1, 5, 8, 9

6 0
2 years ago
Read 2 more answers
A shipping container is in the shape of a right rectangular prism with a length of 2 feet, a width of 1.5 feet, and a height of
Anastaziya [24]

Answer:

5 pounds

Step-by-step explanation:

the volume of the container = 2*1.5*3.5= 10.5cubic foot.

Density of the content = 0.49 pound per cubic foot.

As already know,

Density = mass/ volume.

therefore, mass = density * volume.

mass of the content = 0.49 * 10.5 =5 pounds approximately

6 0
3 years ago
Help me solve this Algebra problem please​
sp2606 [1]

Answer:

39858075

Step-by-step explanation:

Hello,

One basic way to see it is to compute the values.

   75 = 25 * 3

   225 = 75 * 3

   675 = 225 * 3

   etc ...

We can notice that this is multiplied by 3 every 10 years so we can compute as below.

year         population

1970 25

1980 75

1990 225

2000 675

2010 2025

2020 6075

2030 18225

2040 54675

2050 164025

2060 492075

2070 1476225

2080 4428675

2090 13286025

2100 39858075

So the correct answer is 39858075

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0
3 years ago
PLEASE HELP
Alecsey [184]
The number to which a base is raised to is called the _exponent_ This tells you how many times to multiply the base together.
8 0
4 years ago
How is the series 5+11+17…+251 represented in summation notation?
NISA [10]

Answer:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

Step-by-step explanation:

Given:

  • Series 5+11+17+...+251

To find:

  • Summation notation of the given series

Summation Notation:

\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

  • Arithmetic Series

A series that has common difference.

  • Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

  • 11-5 = 6
  • 17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

\displaystyle \large{a_n=a_1+(n-1)d}

Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

And for number of terms, substitute \displaystyle \large{a_n} = 251 and solve for n:

\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

5 0
2 years ago
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