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poizon [28]
3 years ago
14

Four children are fighting over the same toy. Mike is pulling North with a 50 N force, Justin is pulling East with a 40 N force,

Chantal is pulling South with a 50 N force, and Tykera is pulling West a 30 N force. Who gets the toy . Provide evidence to support your claim .
Physics
2 answers:
Musya8 [376]3 years ago
6 0

Answer:

Justin

Explanation:

Given that Four children are fighting over the same toy.

If Mike is pulling North with a 50 N force, Justin is pulling East with a 40 N force, Chantal is pulling South with a 50 N force, and Tykera is pulling West a 30 N force. 

Resolving the forces into horizontal X and vertical Y components.

Vertical component ( north and south)

Since Mike is pulling North with a 50 N force and Chantal is pulling South with a 50 N force,

The net Force = 50 - 50 = 0

Therefore, the net vertical force is equal to zero.

Horizontal component ( west and east)

Since Justin is pulling East with a 40 N force and Tykera is pulling West a 30 N force.

The net force = 40 - 30

The net force = 10 N

Since it is positive, it will be due east.

Therefore, Justin gets the toy.

Phoenix [80]3 years ago
6 0

Answer:

Forces are either positive or negative vectors, depending on the direction in which the force is acting. The net force is the sum of all of the forces acting on an object. If the children pull on the toy with the same force in opposite directions, the forces will be perfectly balanced and cancel out, leaving a net force of zero.

Explanation:

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Lena [83]

Answer:

a. They will be tie

b. Win the wood cylinder

Explanation:

a.

The both cylinders will reach the bottom at the same time notice the relation in the equation in indepent of the length and both have the same radius and the same rotational inertia.

I=\frac{1}{2}*m*r^2

a=\frac{g*sin(\beta)}{1+I_{com}/m*r^2}

So both will be tie

b.

a_{brass}=\frac{g*sin(\beta)}{1+I_{brass}/m*r^2}=a_{wood}=\frac{g*sin(\beta)}{1+I_{wood}/m*r^2}

The acceleration of the wood cylinder is larger than the acceleration of the brass cylinder so the cylinder of wood will reach the bottom first

a_{brass}

So the wood win the race

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3 years ago
Arocket launches at an angle of 33.6 degrees from the horizontal at a
babymother [125]

Answer:

Y component = 32.37

Explanation:

Given:

Angle of projection of the rocket is, \theta=33.6

Initial velocity of the rocket is, u=58.5

A vector at an angle \theta with the horizontal can be resolved into mutually perpendicular components; one along the horizontal direction and the other along the vertical direction.

If a vector 'A' makes angle \theta with the horizontal, then the horizontal and vertical components are given as:

A_x=A\cos \theta(\textrm{Horizontal or X component})\\A_y=A\sin \theta(\textrm{Vertical or Y component})

Here, as the velocity is a vector quantity and makes an angle of 33.6 with the horizontal, its Y component is given as:

u_y=u\sin \theta

Plug in the given values and solve for u_y. This gives,

u_y=(58.5)(\sin 33.6)\\u_y=58.5\times 0.55339\\u_y=32.373\approx32.37(\textrm{Rounded to two decimal places})

Therefore, the Y component of initial velocity is 32.37.

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The plate near the Artic Ridge is among those with the slower growth rates, moving slightly less than 2.5 cm/year. How much will
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Greater than 25 . 2.5 x 10 = 30
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3 years ago
An electron is moving at 7.4x105 m/s perpendicular to a magnetic field. It experiences a force of 2.0x10–13 N. What is the magne
alisha [4.7K]

Answer:

1.69 T

Explanation:

Applying,

F = BvqsinФ.................. Equation 1

Where F = Force, B = magnetic field, v = velocity, q = charge on an electron, Ф = angle between the electron and the field.

make B the subject of the equation,

B = F/(vqsinФ)............. Equation 2

From the question,

Given: F = 2.0×10⁻¹³ N, v = 7.4×10⁵ m/s, Ф = 90°

Constant: q = 1.60×10⁻¹⁹ C

Substitute into equation 2

B =  2.0×10⁻¹³/(7.4×10⁵×1.60×10⁻¹⁹×sin90°)

B = 0.169×10

B = 1.69 T

4 0
3 years ago
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