Answer:
The correct answer is "24 V".
Explanation:
The given values are:
Current,
I = 0.50 A
Resistance,
R = 12 W
As we know,
⇒
On substituting the given values, we get
⇒
⇒
⇒
Samburu's weight is (mass x gravity) = (1650kg x 9.8 m/s²) = 16,170 Newtons.
Samburu's contact area with the ground is (0.25 m²/hoof) x (4 hoofs) = 1 m² .
Pressure = (force) / (area) = (16,170 Newtons) / (1 m²) = 16,170 Pascal .
The answer is .
<h3>What is kinetic energy?</h3>
- A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force.
- Kinetic energy comes in five forms: radiant, thermal, acoustic, electrical, and mechanical.
- The energy of a body in motion, or kinetic energy (KE), is essentially the energy of all moving objects. Along with potential energy, which is the stored energy present in objects at rest, it is one of the two primary types of energy.
- Explain that a moving object's mass and speed are two factors that impact the amount of kinetic energy it will possess.
Determine the escape speed for the rocket from the planet-satellite system:
The potential energy of the rocket due to Ganymede when it is on the surface of the Ganymede is,
The potential energy of the rocket due to Jupiter
when it is on the surface of the Ganymede is,
Here, R is a separation between Jupiter and Ganymede.
To escape from the surface of Ganymede potential energy of the rocket due to Jupiter and Ganymede is equal to the kinetic energy of the rocket.
To learn more about kinetic energy, refer to:
brainly.com/question/25959744
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The problem describes the relationship of "bulb a" and "bulb b" to be in connected in series. When the switch is open then no current can flow, on the other hand, when it is closed, current will pass through.
When only "bulb a" is connected to the battery then more current is flowing to "bulb a" causing it to be bright.
Closing the switch would mean that "bulb b" is already included in the circuit and the battery will push small current to flow around the whole circuit. The more bulbs are connected, the harder for the current to flow because the resistance will be very high.
So the light of "bulb a" will be dimmer.