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Free_Kalibri [48]
3 years ago
12

Break-even analysis is a tool that marketers are likely to employ during the ____ stage of the new-product development process.

Business
1 answer:
Kobotan [32]3 years ago
6 0

business analysis stage, this occurs before development

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The answer is (A)

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Sheridan Company signed a long-term non cancellable purchase commitment with a major supplier to purchase raw materials in 2021
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Unrealized holding loss - Income (purchase commitments) $ 52,900 Dr

Estimated liability on purchase commitments ( $ 1,001,800 - $ 948,900 ) $ 52,900 Cr

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The probability that a randomly selected education major received a starting salary offer greater than $52,350 is . The probabil
AveGali [126]

Answer:

  • <u>1.  0.0808</u>
  • <u>2. 0.5371</u>
  • <u>3. 58.2%</u>

<u></u>

Explanation:

The first part of the question, with the input data, is missing.

This is missing part:

  • <em>Assume that X, the starting salary offer for education majors, is normally distributed with a mean of $46,292 and a standard deviation of $4,320</em>

<h2>Solution</h2><h2 />

<em>Question 1: The probability that a randomly selected education major received a starting salary offer greater than $52,350 is ________</em>

Find the Z-score.

The Z-score is the standardized value of the random variable and represents the number of standard deviations the value of the random variable is away from the mean:

       Z-score=\dfrac{X-\mu}{\sigma}

      Z-score=\dfrac{\$52,350-\$46,292}{\$4,320}=1.40

      P(X>\$52,350)=P(Z>1.40)=P(Z

The<em> standard normal distribution</em> tables give the cumulative probabilities as the cumulative area under the bell-shaped curve. P(Z>1.40) is the area under the curve that is to the right of Z = 1.40 or, what is the same, P(Z<-1.40) is the area to the left of Z = - 1.40.

Using the former, the table indicates P(Z>1.40) = 0.0808, which is 8.08%

<em>Question 2: The probability that a randomly selected education major received a starting salary offer between $45,000 and $52,350 is _______.</em>

Now you  must find the area under the curve between the two Z-scores.

    Z(X=$45,000)=\dfrac{\$45,000-\$46,292}{\$4,320}=-0.30

   Z(X=$52,350)=\dfrac{\$52,350-\$46,292}{\$4,320}=1.40

Then, you must find the area between Z = -0.30 and Z = 1.40

That is P(Z<1.40) - P(Z < - 0.30) = P(Z > - 1.40) - P(Z < - 0.30)

                                                    = 1 - P(Z< -1.40) - P( Z < -0.30)

Now, you can work with the area under the curve to the left of Z = - 1.40 and to the left of Z = - 0.30.

From the corresponding table, that is: 1 - 0.0808 - 0.3821 = 0.5371

<em></em>

<em>Question 3. What percentage of education majors received a starting offer between $38,500 and $45,000? </em>

<em></em>

For X = $38,500:

      Z=\dfrac{\$38,500-\$46,292}{\$4,320}=-1.80

For X = $45,000

     Z = -0.3 (calculated above)

Then, you must find the area under the curve to the right of Z = - 1.80 and to the left of Z = - 0.3

  • P (Z > - 1.80) - P (Z < - 0.3)
  • 1 - P (Z < - 1.80) - P (Z < - 0.3)
  • 1 - 0.0359 - 0.3821 = 0.582 = 58.2%

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