All categories

3 years ago

A girl cut off 2/5 of a ribbon. The piece she cut off was 5 meters long.How

Mathematics

2 answers:

valentinak56 [21]3 years ago

7 0

Answer:

12.5

Step-by-step explanation:

5/2*5=12.5

Alekssandra [29.7K]3 years ago

6 0

Answer:

Your answer is 12.5 meters long

Step-by-step explanation:

so you would want to see how long each 1/5 is so if 2/5 is 5 then 1/5 would be half of that so 2.5 then times that by 5 to get your answer which is 12.5.

You might be interested in

Joe went to the hobby shop and bought 2 model sports cars at $8.95 each and some paints. If he spent a total of $23.65, what was

Gala2k [10]

Since he bought 2 model cars for $8.95 each, he bought both for $17.90. Now, subtract this from the total cost to get the cost of paint. $23.65-$17.90=$5.75. So, the total costs of paints are $5.75. Hope this helped!

8 0

3 years ago

The gable end of the roof shown is divided in half by a vertical brace. Find the distance h (in ft) from an eave to the peak. 41

nlexa [21]

Answer:

h = 9 ft

Step-by-step explanation:

Assume the diagram is like the one below.

∆ABD is a right triangle.

We can use Pythagoras' Theorem to find the height h.

$\begin{array}{rcl}h^{2} + 40^{2} & = & 41^{2}\\h^{2} + 1600 & = & 1681\\h^{2} & = & 1681 - 1600\\& = &81\\h& = & \sqrt{81}\\&=& \mathbf{9}\end{array}\\\text{The height of the gable is $\large \boxed{\textbf{9 ft}}$}$

8 0

3 years ago

Find f(-1) if f(x) = -2x^2 -x

kykrilka [37]

I hope it was helpful to you

if u like follow me

3 0

3 years ago

How do you find the value of x?

Lelechka [254]

Lenth*with*height...

5 0

3 years ago

A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec

zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0

3 years ago