Answer:
After 1023.4 years the mass of the substance will be 30 g.
Explanation:
Hi there!
Let´s write the function (according to what I found on the web):
We have to find the time "t1" at which the mass of the substance is 30 g. Mathematically:
m(t1) = 30
Then:
Let´s solve the equation for t1. First, divide by 100 both sides of the equation:
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Apply ln to both sides of the equation:
Use the logarithm property: ln (aᵇ) = b ln(a)
ln(0.3) = -t/850 · ln (e) (ln (e) = 1)
ln(0.3) = -t/850
850 ln(0.3) = -t
t = -850 ln(0.3)
t = 1023.4
After 1023.4 years the mass of the substance will be 30 g.
Example of weathering and erosion:
- The ocean beating up against the cliff of a wall and slowly wearing away rock
- A river flowing through river banks and the bank slowly stretching apart further and further as time goes on
- Water freezes in a crack on a rock. As the water freezes, the crack expands on the rock.
- A plant is planted in the same spot every year and slowly breaks up the soil.
- Acid rain slowly breaks down the structure of a building.
Incomplete question as the charge density is missing so I assume charge density of 3.90×10^−12 C/m².The complete one is here.
An electron is released from rest at a distance of 0 m from a large insulating sheet of charge that has uniform surface charge density 3.90×10^−12 C/m² . How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 3.00×10−2 m from the sheet?
Answer:
Work=1.06×10⁻²¹J
Explanation:
Given Data
Permittivity of free space ε₀=8.85×10⁻¹²c²/N.m²
Charge density σ=3.90×10⁻¹² C/m²
The electron moves a distance d=3.00×10⁻²m
Electron charge e=-1.6×10⁻¹⁹C
To find
Work done
Solution
The electric field due is sheet is given as
E=σ/2ε₀
Now we need to find force on electron
Now for Work done on the electron
Answer:
90 km/h
Explanation:
we just divide the distance by the time to get the speed.
Answer:
The position of the ammeter is in series down the component. While the voltmeter must be connected in parallel. Its position is the gap through the component C.
The positions of one or the other are indicated in the image.
Explanation:
An ammeter is defined as a device used to measure current. Its unit is the ampere. While a voltmeter is used in the measurement of the potential difference between two points. Its unit is the volt. The ammeter must be connected in series with the point at which the current is to be measured, while the voltmeter must be connected in parallel.