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joja [24]
3 years ago
10

PLEASE HELP WITH THIS QUESTION. ​

Physics
1 answer:
Sophie [7]3 years ago
6 0

Answer:

#2 and #3 respectively

Explanation:

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Two precautions in images of a convex lens
yan [13]

Answer:

1 . rays should passs through correct center or points(i.e. optic center or focus)

2.your line representing rays should be straight and u should tell the nature of image

Explanation:

5 0
4 years ago
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A 296-kg motorcycle is accelerating up along a ramp that is inclined 26.2° above the horizontal. The propulsion force pushing th
Alexeev081 [22]

Answer:

The magnitude of the motorcycle's acceleration is 5.20 m/s².

Explanation:

Given that,

Mass of motorcycle = 296 kg

Angle = 26.2°

Force on motorcycle= 3106 N

Force = 286 N

We need to calculate the magnitude of the motorcycle's acceleration

The net force acting on the motorcycle

Using newton's second law

ma=F_{p}-F_{air}-F_{g}

ma=F_{p}-F_{air}-mg\sin\theta

Put the value into the formula

296a=3106-286-296\times9.8\times\sin26.2

a=\dfrac{3106-286-296\times9.8\times\sin26.2}{296}

a=5.20\ m/s^2

Hence, The magnitude of the motorcycle's acceleration is 5.20 m/s².

5 0
3 years ago
Learning Goal: To practice Problem-Solving Strategy 7.1 Rotational dynamics problems. Suppose that you are holding a pencil bala
aliya0001 [1]

Answer:

when the pencil is balanced on a point it is motionless due to net force only acting trough the center, but when we release the position we are changing the location of a pencil hence due to turning affect it will expericence torque and the angular acceleration produced.

for the complete answer the length and mass of pencil should be known i am giving the general expression for the calculation of angular acceleration

Explanation:

<h3>τ=Iα</h3><h3>τ= torque</h3><h3>I = inertia</h3><h3>α= angular acceleration</h3>

where

I= mL^2/3 (by geometry of pencil)

when the pencil is released it will experience force due to weight

F=mgsinθ

so τ=Fxd

τ=mgsin(10°)x(L/2)

then.

α=τ/I

α=mgsin(10°)xL/2÷(mL^2)/3

6 0
3 years ago
A dog of mass 4 kg runs up a hill of height 8 m. How much gravitational potential energy does the dog gain?
Genrish500 [490]
A. 314 because when you use the formula for the GPE ; GPE=MGH or means mass times gravity time height (4x8x9.8) and thats equivalent to 313.6 which rounds up to 314. Hope it helps 
8 0
4 years ago
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A force of 8,480 N is applied to a cart to decelerate it at a rate of 32.0 m/s2. What is the mass of the cart?
GuDViN [60]
The realtionship between force in Newtons, mass in kilograms and acceleration in metres per second squared is described by Newton's second law of motion which is Force = mass times acceleration, or F=ma.  You need to know the mass, so rearrange the formula to solve for m, giving m=F/a
In your example, the mass is therefore  8480 divided by 32, which is equal to 265kg.
3 0
3 years ago
Read 2 more answers
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