All categories

3 years ago

In North America, where is population density the highest ?

Chemistry

1 answer:

zepelin [54]3 years ago

3 0

Near the coasts and Great Lakes.

You might be interested in

How to balance the question?

umka21 [38]

Answer:

CH4 + 2O2 —> CO2 + 2H2O

CH4 + 2O2

C = 1

H = 4

O = 2 ×2 = 4

__o_o___

CO2 + 2H20

C = 1

H = 2 × 2 = 4

O = 2 + 2 = 4

So ; 1 C , 4 H , 4 O

I hope I helped you^_^

4 0

2 years ago

A student prepares a aqueous solution of butanoic acid . Calculate the fraction of butanoic acid that is in the dissociated form

ella [17]

Answer:

15.4%

Explanation:

If Ka = 0.54 mM = 1.51x10⁻⁵

Then;

C₄H₈O₂ --------> C₄H₇O₂⁻ + H⁺

I 0.54x10⁻³ 0 0

E 0.54x10⁻³(1-x) 0.54x10⁻³x 0.54x10⁻³x

Recall that x is the percentage degree of dissociation

From the ICE table;

Ka = [C₄H₇O₂⁻] [ H⁺]/[C₄H₈O₂]

1.51x10⁻⁵=(0.54x10⁻³x) (0.54x10⁻³x)/ 0.54x10⁻³(1-x)

1.51x10⁻⁵ = 0.54x10⁻³x^2/1-x

1.51x10⁻⁵(1-x) = 0.54x10⁻³x^2

1.51x10⁻⁵ - 1.51x10⁻⁵x = 0.54x10⁻³x^2

Hence;

0.54x10⁻³x^2 + 1.51x10⁻⁵x - 1.51x10⁻⁵=0

x^2 + 0.028x - 0.028 = 0

Solving the quadratic equation here;

x = 0.154 or −0.182

Ignoring the negative result, x = 0.154

Hence, fraction of butanoic acid that is in the dissociated form in this solution = 15.4%

3 0

2 years ago

What would cause a liquid to turn into a solid?

KIM [24]

It’s C
Cooling a liquid til it freezes will cause a liquid to turn into a solid

3 0

2 years ago

Read 2 more answers

In the molar volume of a gas lab, a student

GREYUIT [131]

Answer:

Explanation:

8 0

3 years ago

When a 21.5-g sample of LiCl was added to 195 g of water at a temperature of 20.00°C in a calorimeter, the temperature increased

Paha777 [63]

Answer:

$63.09KJ/mol$

Explanation:

In this case, to calculate the heat of solution (KJ/mol) we have to take into account the mass of water, the specific heat of the water and the temperature change, so:

$m=195~g$

$c=4.18~J/g^{\circ}C$

Δ $T=39.26^{\circ}C$

With this in mind, we can use the equation:

$Q=m*c*T$

If we plug the values into the equation we will have:

$Q=195~g*4.18~J/g^{\circ}C*39.26^{\circ}C$

$Q=32000.83~J$

Now, with the mass value (21.5 g) and the molar mass of LiCl (42.39g/mol) we can calculate the moles of LiCl:

$21.5~g~LiCl\frac{1~mol~LiCl}{42.39~g~LiCl}=0.507~mol~LiCl$

Now, in the heat of solution, we have KJ/mol units. Therefore, we have to convert from J to KJ:

$32000.83~J\frac{1~KJ}{1000~J}=32~KJ$

Finally, we can divide by the moles of LiCl:

$\frac{32~KJ}{0.507~mol}=63.09KJ/mol$

So, for each mole of LiCl, we have 63.09 KJ involved in the dissolution process.

I hope it helps!

8 0

3 years ago