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3 years ago

What is nuclear fission

2 answers:

swat323 years ago

5 0

Nuclear fission is the process of which a large nucleus splits into two smaller nuclei with the release of energy and neutron. In simpler words, nuclear fission is the process in which a nucleus is split into two smaller fragments or pieces (nuclei) and so energy and neutrons are released. The resulting pieces of this fission process have less combined mass than the original piece (nucleus) and the missing was is converted into nuclear energy.

nataly862011 [7]3 years ago

3 0

A nuclear reaction in which a heavy nucleus splits spontaneously or on impact with another particle, with the release of energy.

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Determine two complex numbers, (a+bi) and (c+di), where a and d are irrational numbers and b and c are rational number

Dafna11 [192]

Answer:

The two complex numbers are $\sqrt2 + 5i \text{ and } 6 + \sqrt5i$

Explanation:

We have to form two complex numbers of the form

$a + ib\\c + id$

such that and d are irrational numbers and b and c are rational numbers.

We know that $\sqrt2, \sqrt3$ are irrational numbers.

5 and 6 are rational numbers.

We put

$a = \sqrt2\\b = 5\\c = 6\\d = \sqrt5\\a+ib = \sqrt2 + 5i\\c + id = 6 + \sqrt5i$

Thus, the two complex numbers are: $\sqrt2 + 5i \text{ and } 6 + \sqrt5i$

7 0

2 years ago

Read 2 more answers

what is the approximate ph at the equivalence point of a weak acid-strong base titration if 25 ml of aqueous formic acid require

vivado [14]

Answer:

pH at equivalence point is 8.52

Explanation:

$HCOOH+NaOH\rightarrow HCOO^{-}Na^{+}+H_{2}O$

1 mol of HCOOH reacts with 1 mol of NaOH to produce 1 mol of $HCOO^{-}$

So, moles of NaOH used to reach equivalence point equal to number of moles $HCOO^{-}$ produced at equivalence point.

As density of water is 1g/mL, therefore molarity is equal to molality of an aqueous solution.

So, moles of $HCOO^{-}$ produced = $\frac{29.80\times 0.3567}{1000}moles=0.01063moles$

Total volume of solution at equivalence point = (25+29.80) mL = 54.80 mL

So, at equivalence point concentration of $HCOO^{-}$ = $\frac{0.01063\times 1000}{54.80}M=0.1940M$

At equivalence point, pH depends upon hydrolysis of $HCOO^{-}$ . So, we have to construct an ICE table.

$HCOO^{-}+H_{2}O\rightleftharpoons HCOOH+OH^{-}$

I: 0.1940 0 0

C: -x +x +x

E: 0.1940-x x x

So, $\frac{[HCOOH][OH^{-}]}{[HCOO^{-}]}=K_{b}(HCOO^{-})=\frac{10^{-14}}{Ka(HCOOH)}$

species inside third bracket represent equilibrium concentrations

So, $\frac{x^{2}}{0.1940-x}=5.56\times 10^{-11}$

or, $x^{2}+(5.56\times 10^{-11}\times x)-(1.079\times 10^{-11})=0$

So, $x=\frac{-(5.56\times 10^{-11})+\sqrt{(5.56\times 10^{-11})^{2}+(4\times 1.079\times 10^{-11})}}{2}$

So, $x=3.285\times 10^{-6}M$

So, $pH=14-pOH=14+log[OH^{-}]=14+logx=14+log(3.285\times 10^{-6})=8.52$

5 0

2 years ago

Complete the nuclear reaction.*

irina [24]

$\boxed {_{-1}^0e}$

Explanation:

$\huge _{53}^{125}I\rightarrow _{54}^{125}Xe+\boxed {_{-1}^0e}$

5 0

2 years ago

Which element in period 2 has six electrons in its electron dot structure?

navik [9.2K]

Answer:

calcium

Explanation:

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3 years ago

Can someone pls give me the answer to this question?

Svetllana [295]

Answer:

Explanation:

5 0

2 years ago