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aliya0001 [1]
3 years ago
15

What is nuclear fission

Chemistry
2 answers:
swat323 years ago
5 0
Nuclear fission is the process of which a large nucleus splits into two smaller nuclei with the release of energy and neutron. In simpler words, nuclear fission is the process in which a nucleus is split into two smaller fragments or pieces (nuclei) and so energy and neutrons are released. The resulting pieces of this fission process have less combined mass than the original piece (nucleus) and the missing was is converted into nuclear energy.
nataly862011 [7]3 years ago
3 0
A nuclear reaction in which a heavy nucleus splits spontaneously or on impact with another particle, with the release of energy.
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Elements with atomic numbers 7 and 83 have how many valence electrons? *
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Explanation:

element with atomic numbers 7 and 83 have 5 and 5 valence electrons

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What is the minimum amount of heat required to completely melt 40.0 grams of ice at its melting point?
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If 20.0 grams of ice takes about 6680j...then 40.0 grams of ice would take ___ .
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A person's heartbeat is 89 beats per minute. If his/her heart beats 3.1e9 times in a lifetime, how long (in whole years) does th
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A 3.0 g sample of a gas occupies a volume of 1.00L at 100C and 740 torr pressure. The molecular weight of the
SOVA2 [1]

Answer:

94.2 g/mol

Explanation:

Ideal Gases Law can useful to solve this

P . V = n . R . T

We need to make some conversions

740 Torr . 1 atm/ 760 Torr = 0.974 atm

100°C + 273 = 373K

Let's replace the values

0.974 atm . 1 L = n . 0.082 L.atm/ mol.K . 373K

n will determine the number of moles

(0.974 atm . 1 L) / (0.082 L.atm/ mol.K . 373K)

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3 0
3 years ago
The standard cell potential Ec for the reduction of silver ions with elemental copper is 0.46V at 25 degrees celsius. calculate
Cloud [144]

Answer : The \Delta G for this reaction is, -88780 J/mole.

Solution :

The balanced cell reaction will be,  

Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half oxidation-reduction reaction will be :

Oxidation : Cu\rightarrow Cu^{2+}+2e^-

Reduction : 2Ag^++2e^-\rightarrow 2Ag

Now we have to calculate the Gibbs free energy.

Formula used :

\Delta G^o=-nFE^o

where,

\Delta G^o = Gibbs free energy = ?

n = number of electrons to balance the reaction = 2

F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole

Therefore, the \Delta G for this reaction is, -88780 J/mole.

7 0
3 years ago
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