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astra-53 [7]
3 years ago
6

In the molar volume of a gas lab, a student

Chemistry
1 answer:
GREYUIT [131]3 years ago
8 0

Answer:

A

Explanation:

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Is this better to see than the other one
Nimfa-mama [501]
Number 2. This is a power plant windmill. Kinetic energy from the wind is being converted to mechanical energy. 

Number 3. Those are energy power plants which involve coal being burned. Chemical energy is being converted to heat energy and then into kinetic energy.

Number 3. You're welcomed to use whatever object you'd like. An example you could put is a car. Chemical energy is being converted to mechanical energy. 

Hope that helps. -UF aka Nadia
8 0
3 years ago
10 points) Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, a
IceJOKER [234]

Answer:

The over all reaction :

2Fe^{3+}(aq)+Pb(s)\rightarrow 2Fe^{2+}(s)+Pb^{2+}(aq)  

The standard cell potential of the reaction is 0,.897 Volts.

Explanation:

Reduction at cathode :

Fe^{3+}(aq)+e^-\rightarrow Fe^{2+}(s)..[1]  

E^o_{Fe^{3+}/Fe^{2+}}=0.771 V

Reduction potential of Fe^{3+} to Fe^{2+}=0.771 V

Oxidation at anode:

Pb(s)\rightarrow Pb^{2+}(aq)+2e^-.[2]

E^o_{Pb^{2+}/Pb}=-0.126 V

Reduction potential of Pb^{3+} to Pb=-0.126 V

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

Putting values in above equation, we get:

E^o_{cell}=E^o_{Fe^{3+}/Fe^{2+}}-E^o_{Pb^{2+}/Pb}

=0.771 V-(-0.126 )=0.897 V

The over all reaction : 2 × [1] + [2]

2Fe^{3+}(aq)+Pb(s)\rightarrow 2Fe^{2+}(s)+Pb^{2+}(aq)  

The standard cell potential of the reaction is 0,.897 Volts.

7 0
3 years ago
A wave is moving towards shore with a velocity of 5.0 MS if it’s frequency is 2.5 Herz what is the wave length
EastWind [94]

Answer:

<h2>2 m</h2>

Explanation:

The wavelength of a wave can be found by using the formula

\lambda =  \frac{c}{f}  \\

where

c is the speed of the wave

f is the frequency

From the question

c = 5 m/s

f = 2.5 Hz

We have

\lambda =  \frac{5}{2.5}  = 2 \\

We have the final answer as

<h3>2 m </h3>

Hope this helps you

8 0
3 years ago
Calculate the approximate enthalpy of the reaction in joules. Estimate that 1.0 mL of vinegar has the same thermal mass as 1.0 m
Nesterboy [21]

Explanation:

The given data is as follows.

   Density of vinegar = 1.0 g/ml

   Specific heat capacity = 4.25 J/g ^{o}C

   T_{1} = 17 ^{o}C,  and   T_{2} = 14 ^{o}C

Relation between enthalpy and specific heat is as follows.

                   \Delta H = mC \Delta T

Hence, putting the values into the above formula as follows.

          \Delta H = mC \Delta T

                  = 25 \times 1.0 \times 4.25 J/g ^{o}C \times -3^{o}C          (as density = \frac{mass}{volume})

                               = - 315 J

Thus, we can conclude that the enthalpy of reaction is -315 J.

As the value is negative so, it means that heat is releasing. Hence, the reaction is exothermic in nature.

5 0
3 years ago
Calculate the work done when a force of 500N moves an object 20m. and (B) if it
strojnjashka [21]

Answer:

work done = force multiplied by distance covered,which is 500n multiplied by 20 m= 10000nm

power= work done/time

p= 10000/10

p=1000

4 0
3 years ago
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