Answer:
34.6 cm³
Explanation:
Given data
- Mass of carbon tetrachloride (m): 55.0 g
- Density of carbon tetrachloride (ρ): 1.59 g/cm³
- Volume of carbon tetrachloride (V): ?
We can determine the volume of carbon tetrachloride that the student should pour out using the following expression.
ρ = m / V
V = m / ρ
V = 55.0 g / (1.59 g/cm³)
V = 34.6 cm³
Ozone is mainly found in two regions of the Earth's atmosphere. Most ozone (about 90%) resides in a layer that begins between 6 and 10 miles (10 and 17 kilometers) above the Earth's surface and extends up to about 30 miles (50 kilometers). This region of the atmosphere is called thestratosphere.
Explanation:
For the given values of we will have the values of as follows.
As,
Therefore,
= 2.15, = 7.20
= 12.38
Now, at pH 6.50
;
At pH = 2.15;
;
At pH 7.20;
;
Hence, we can conclude that most abundant species is and the second most abundant species is .