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zaharov [31]
3 years ago
13

A chemistry student needs 55.0g of carbon tetrachloride for an experiment. by consulting the crc handbook of chemistry and physi

cs, the student discovers that the density of carbon tetrachloride is 1.59·gcm−3 . calculate the volume of carbon tetrachloride the student should pour out.
Chemistry
1 answer:
Tanzania [10]3 years ago
4 0

Answer:

34.6 cm³

Explanation:

Given data

  • Mass of carbon tetrachloride (m): 55.0 g
  • Density of carbon tetrachloride (ρ): 1.59 g/cm³
  • Volume of carbon tetrachloride (V): ?

We can determine the volume of carbon tetrachloride that the student should pour out using the following expression.

ρ = m / V

V = m / ρ

V = 55.0 g / (1.59 g/cm³)

V = 34.6 cm³

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Answer:

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Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

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Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

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