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2 years ago

Do you think climate change is a hoax or is it a scientifically valid disrupter of ecosystems?

Chemistry

2 answers:

Ksju [112]2 years ago

7 0

Answer:

Climate change is a scientifically valid disrupter of exosystems. People need to do something to change their actions or we won't have a future to live in. We don't need to end emissions but completly halt all fossil fuel exploration and extraction now and completly divest from fossil fuels all together.

DO NOT COPY

Monica [59]2 years ago

3 0

Answer:

it is actually valid.

Explanation:

Take a look at the arctic for example. Global warming caused a change within that climate. Icebergs are melting and predators such as polar bears are losing their food sources. They may soon go extinct.

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The curiosity is important in the progress of science because it

nordsb [41]

It it important because it makes people wonder how things work and are made which makes it so they want to move forward with experiments <span />

3 0

3 years ago

Read 2 more answers

According to the Arrhenius equation, changing which factors will affect the

slamgirl [31]

Answer:

e−(Ea/RT): the fraction of the molecules present in a gas which have energies equal to or in excess of activation energy at a particular temperature

6 0

2 years ago

Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under eac

valentinak56 [21]

Answer : The value of $\Delta G_{rxn}$ is, $8.867kJ/mole$

Explanation :

The formula used for $\Delta G_{rxn}$ is:

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction

$\Delta G_^o$ = standard Gibbs free energy

R = gas constant = 8.314 J/mole.K

T = temperature = $25^oC=273+25=298K$

Q = reaction quotient

First we have to calculate the $\Delta G_^o$ .

Formula used :

$\Delta G^o=-RT\times \ln K_p$

Now put all the given values in this formula, we get:

$\Delta G^o=-(8.314J/mole.K)\times (298K)\times \ln (2.26\times 10^{4})$

$\Delta G^o=-24839.406J/mole=-24.83\times 10^3J/mole=-24.83kJ/mole$

Now we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

$CO(g)+2H_2(g)\rightarrow CH_3OH(g)$

The expression for reaction quotient will be :

$Q=\frac{(p_{CH_3OH})}{(p_{CO})\times (p_{H_2})^2}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(1.4)}{(1.2\times 10^{-2})\times (1.2\times 10^{-2})^2}$

$Q=8.1\times 10^{5}$

Now we have to calculate the value of $\Delta G_{rxn}$ by using relation (1).

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$

Now put all the given values in this formula, we get:

$\Delta G_{rxn}=-24.83kJ/mole+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (8.1\times 10^{5})$

$\Delta G_{rxn}=8.867\times 10^3J/mole=8.867kJ/mole$

Therefore, the value of $\Delta G_{rxn}$ is, $8.867kJ/mole$

3 0

2 years ago

According to Newton's Third Law, If one object exerts a force on a second object, the second object exerts a force on the first

blagie [28]

Equal in magnitude and opposite in direction.

3 0

2 years ago

...............………...mkmlkml;m

bagirrra123 [75]

Answer:

390

Explanation:

Specific heat capacity= heat/mass × temperature

$x = 2925 \div 0.5 \times 15 = 390$

Remember you convert gram into kilogram and 1 gram =0.001 kilogram

5 0

2 years ago