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ad-work [718]
4 years ago
12

Espresso Coffee House is designing a coffee mug that keeps liquids hot. The research department tested several different materia

ls for their ability to keep a normal-sized cup of coffee hot the longest amount of time. The testing room temperature is approximately 25 degrees Celsius. Write a scientific explanation to justify the selection of material, A, B, or C, used to create the cup that would keep the coffee the hottest for the longest period of time.
Chemistry
1 answer:
raketka [301]4 years ago
4 0

Answer:

This question is incomplete

Explanation:

This question is incomplete because the result of the described experiment would have better determined the type of scientific explanation to profer. However, the type of material that will preserve the relative hotness or temperature of the hot coffee for the longest time will be a material than can resist heat transfer. These materials tend to keep hot substances hot by not allowing the heat of the coffee to be conducted or pass through it. These materials are mostly insulators or made by placing an insulator between two heat conductors.

Generally, heat is usually transferred from a region of higher concentration to a region of lower concentration, hence when the heat is denied of this transfer, the heat will remain trapped in the "heat-donor" substance (in this case the hot coffee). Thus, the material chosen (A, B or C) will be the material that resists heat transfer the most based on the explanation above.

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MakcuM [25]

Answer:

\lambda=6.56x10^{-7}m

Explanation:

Hello there!

In this case, it possible to use the Rydberg equation in order to calculate the wavelength for this transition from n=3 to n=2 as shown below:

\frac{1}{\lambda} =R_H(\frac{1}{n_f^2}-\frac{1}{n_i^2} )

Thus, we plug in the corresponding energy levels and the Rydberg constant to obtain:

\frac{1}{\lambda} =10973731.6m^{-1}(\frac{1}{2^2}-\frac{1}{3^2} )\\\\\frac{1}{\lambda} =1524129.4m^{-1}\\\\\lambda=\frac{1}{1524129.4m^{-1}} \\\\\lambda=6.56x10^{-7}m

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3 years ago
What type of central-atom orbital hybridization corresponds to each electron-group arrangement:
galina1969 [7]

Tetrahedral arrangement is resulted upon mixing one s and three p atomic orbitals, resulting in 4 hybridized sp^3 orbitals → sp^3 hybridization.

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

Learn more about Hybridization

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3 0
2 years ago
The _______ of a wave is a measure of the amount of energy it carries
Bumek [7]
The word that best fits is frequency. The sentence is The frequency of a wave is a measure of the amount of energy it carries. There is a direct relationship between frequency and energy of a wave. The constant of proportionality is h, Planck's constant. So, Energy = h * frequency. So, the answer is frequency.<span> Although you should know that wavelength is related to frequency and so it is also a measure of the amount of energy and it should also be other valid answer.</span>
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Explanation:

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fiasKO [112]

Answer:

Yes

Explanation:

Neither Calcium nor hydrogen nor oxygen are alkali metals

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Here

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As it's greater than 1 it's a very strong base .

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Strong Alkali

3 0
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