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4 years ago

Describe what subatomic particle is involved in light emission.

Chemistry

1 answer:

KiRa [710]4 years ago

8 0

Answer:

Option C= light is emitted as electron falls from the excited state to the ground state releasing a photon.

Explanation:

Electrons are responsible for the production of colored light.

Electron:

The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.

Symbol= e-

Mass= 9.10938356×10⁻³¹ Kg

It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.

How electrons produce the colored light:

Excitation:

When the energy is provided to the atom the electrons by absorbing the energy jump to the higher energy levels. This process is called excitation. The amount of energy absorbed by the electron is exactly equal to the energy difference of orbits.

De-excitation:

When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum.

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What reacts at room temperature with ethanol and also with ethanoic acid

solniwko [45]

Answer: Its esterification reaction.

when organic acid react with alcohol it forms ester and water. reaction is known as esterification reaction.

CH3COOH + C2H5OH → CH3COOC2H5 + H2O

ethanoic acid + ethanol → ethyl acetate + water

this reaction takes place in the presence of acid catalyst ( dil H2SO4).

in this reaction oxygen of ethanol with lone pair act as nucleophile and carbonyl carbon of acetic acid act as electrophile.. so its nucleophilic substitution reaction of -COOH group.

Explanation:

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3 years ago

Read 2 more answers

Give the common name for the structure. ethyl isopropyl ketone tert-butyl ethyl ketone sec-butyl ethyl ketone ethyl isobutyl ket

salantis [7]

The structure for this question is attached. I think the correct answer would be the fourth option. The common name of the structure would be ethyl isobutyl ketone. Other name would be 2-methyl-3-pentanone. It has a chemical formula of C7H14O or (CH3)2CHCH2C(O)CH2CH3. It is classified as an aliphatic ketone and is used as a solvent and a reagent in laboratory experiments. It is a VOC or volatile organic compound. This compound can also be found at times in normal human biofluids and in feces for about 25% of the population. At normal conditions, it exists as a solid compound.

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4 years ago

Jake hangs two balloons from a desk so that they are close together but not touching. Jake rubs one balloon with a wool cloth. H

pav-90 [236]

The objects that are rubbed together will create charges among themselves due to friction.
(1) The balloon rubbed with a wool cloth will be charged.
(2) If she comb near a small, uncharged object nothing will change.
(3) This is a scientific investigation because it does not involved a step by step process to answer a scientific query.

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4 years ago

Read 2 more answers

Calculate the total energy, in kilojoules, that is needed to turn a 46 g block

gogolik [260]

Answer: The amount of heat absorbed is 141.004 kJ.

Explanation:

In order to calculate the amount of heat released while converting given amount of steam (gaseous state) to ice (solid state), few processes are involved:

(1): $H_2O (s) (-25^oC, 248K) \rightleftharpoons H_2O(s) (0^oC,273K)$

(2): $H_2O (s) (0^oC, 273K) \rightleftharpoons H_2O(l) (0^oC,273K)$

(3): $H_2O (l) (0^oC, 273K) \rightleftharpoons H_2O(l) (100^oC,373K)$

(4): $H_2O (l) (100^oC, 373K) \rightleftharpoons H_2O(g) (100^oC,373K)$

Calculating the heat absorbed for the process having the same temperature:

$q=m\times \Delta H_{(f , v)}$ ......(i)

where,

q is the amount of heat absorbed, m is the mass of sample and $\Delta H_{(f , v)}$ is the enthalpy of fusion or vaporization

Calculating the heat released for the process having different temperature:

$q=m\times C_{s,l}\times (T_2-T_1)$ ......(ii)

where,

$C_{s,l}$ = specific heat of solid or liquid

$T_2\text{ and }T_1$ are final and initial temperatures respectively

For process 1:

We are given:

$m=46g\\C=2.108J/g^oC\\T_2=0^oC\\T_1=-25^oC$

Putting values in equation (i), we get:

$q_1=46g\times 2.108J/g^oC\times (0-(-25))\\\\q_1=2424.2J$

For process 2:

We are given:

$m=46g\\\Delta H_{fusion}=334J/g$

Putting values in equation (i), we get:

$q_2=46g\times 334J/g\\\\q_2=15364J$

For process 3:

We are given:

$m=46g\\C=4.186J/g^oC\\T_2=100^oC\\T_1=0^oC$

Putting values in equation (i), we get:

$q_3=46g\times 4.186J/g^oC\times (100-0)\\\\q_3=19255.6J$

For process 4:

We are given:

$m=46g\\\Delta H_{vap}=2260J/g$

Putting values in equation (i), we get:

$q_4=46g\times 2260J/g\\\\q_4=103960J$

Calculating the total amount of heat released:

$Q=q_1+q_2+q_3+q_4$

$Q=[(2424.2)+(15364)+(19255.6)+(103960)]$

$Q=141003.8J=141.004kJ$ (Conversion factor: 1 kJ = 1000J)

Hence, the amount of heat absorbed is 141.004 kJ.

7 0

3 years ago

If a stock solution of 20.0 g of sugar per 100. ml of solution is available, how much of this stock is needed to prepare 10.0 ml

Vladimir79 [104]

You must use 2.50 mL of the concentrated solution to make 10.0 mL of the dilute solution.

We can use the dilution formula

V_1C_1 = V_2C_2

where

V represents the volumes and

C represents the concentrations

We can rearrange the formula to get

V_2 = V_1 × (C_1/C_2)

V_1 = 10.0 mL; C_1 = 5.00 g/100. mL

V_2 = ?; ____C_2 = 20.0 g/100. mL

∴ V_2 = 10.0 mL × [(5.00 g/100. mL)/(20.0 g/100. mL)] = 10.0 mL × 0.250

= 2.50 mL

3 0

3 years ago