To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m
The potential difference is related to the electric field by:
∆V=Ed
where,
∆V is the potential difference
E is the electric field
d is the distance
what is potential difference?
The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.
We want to know the distance the detectors have to be placed in order to achieve an electric field of
E=1v/cm=100v/cm
when connected to a battery with potential difference
∆v=1.5v
Solving the equation,we find
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Answer:
g = 0.85 m
Explanation:
g =
were; g is the acceleration due to Earth's gravity, G is Newton's gravitation constant (6.674 x N), M is the mass of the earth (5.972 x kg), and h is the distance of meteoroid to the earth.
h = 3.40 x R
= 3.40 x 6371 km
h = 21661.4 km
= 21661400 m
Thus,
g =
=
= 0.84944
g = 0.85 m
The acceleration due to the Earth's gravitation is 0.85 m.
Answer:
They become the same exact tempature
Explanation:
Since they got connected it should be the same.
Explanation:
As the given data is as follows.
ohm, ohm,
= 1200 (as 1 k ohm = 1000 m)
(a) We will calculate the maximum resistance by combining the given resistances as follows.
Max. Resistance =
= ohm
= 2600 ohm
or, = 2.6 ohm
Therefore, the maximum resistance you can obtain by combining these is 2.6 ohm.
(b) Now, the minimum resistance is calculated as follows.
Min. Resistance =
=
= ohm
Hence, we can conclude that minimum resistance you can obtain by combining these is ohm.
Answer:
()=1913.31 N/m^2
Explanation:
given:
=0.85
=90 m/s
γ∞=1.23 kg/m^3
solution:
since outside pressure is atm pressure vaccum can be defined by ()
=√2()/γ∞[-1]
()=1913.31 N/m^2