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3 years ago

1) Determine the magnitude of energy for each of the blanks on the diagram. Give the correct values for 1A, 1B, and 1C.

Physics

1 answer:

morpeh [17]3 years ago

4 0

Answer:

Explanation: y’all taking the same test as me hahahahah I got the answers but I can’t attach the picture here so hit me up on snap daniela_0789

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How much kinetic energy does a 55 kg object have that is traveling 20m/s?

shutvik [7]

Answer:

11000 J

Explanation:

Apply the formula: K = 1/2.m.v²

K = 1/2.55.20²

K = 1/2.55.400

K = 55.200

K = 11000 Joules

4 0

3 years ago

Read 2 more answers

A mixture consists of sand, salt, and iron filings. Which of the following instruments or materials would not be useful in separ

Zanzabum

Well water would prob be your best bet, you could extract the salt first and then use a magnet to seperate the iron filing from the sand

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4 years ago

Driving along a crowded freeway, you notice that it takes a time tt to go from one mile marker to the next. When you increase yo

ddd [48]

Answer:

38.6 mi/h

Explanation:

7.4 mi/h = 7.4mi/h * (1/60)hour/min * (1/60) min/s = 0.00206 mi/s

Let v (mi/s) be your original speed, then the time t it takes to go 1 mi/s is

t = 1/v

Since you increase v by 0.00206 mi/s, your time decreases by 15 s, this means

t - 15 = 1/(v+0.00206)

We can substitute t = 1/v to solve for v

$\frac{1}{v} - 15 = \frac{1}{v + 0.00206}$

We can multiply both sides of the equation with v(v+0.00206)

v+0.00206 - 15v(v+0.00206) = v

$-15v^2 - 0.0308v + 0.00206 = 0$

$v= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$v= \frac{0.03083\pm \sqrt{(-0.03083)^2 - 4*(-15)*(0.00205)}}{2*(-15)}$

$v= \frac{0.03083\pm0.35}{-30}$

v = -0.01278 or v = 0.01 0724 mi/s

Since v can only be positive we will pick v = 0.010724 mi/s or 0.010724*3600 = 38.6 mi/h

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4 years ago

Which of the following atmospheric conditions are needed to create the winds?

Talja [164]

Answer:

is there suppose to be a pic?

Explanation:

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3 years ago

Read 2 more answers

If a book is knocked off a desk that is .75 m tall at a rate of 2.0 m/s, how far away from the desk does it fall

ANEK [815]

Answer: 0.8 m

Explanation:

In the vertical direction, the speed is zero, u = 0.

Distance covered in the vertical direction, s = 0.75 m.

The book would fall with acceleration due to gravity in the vertical direction, a = g = 9.8 m/s²

From the equation of motion,

s = u t + 0.5 a t²

Substituting the above values, we will find out the time taken for the book to hit the ground.

⇒0.75 m=0+0.5×9.8 m/s²×t²

⇒t = √0.153 = 0.39 s ≈ 0.40 s

Now, the horizontal distance covered,

d = v×t ⇒d= 2.0 m/s × 0.40 s =0.8 m

Hence, the book falls 0.8 m away from the desk.

7 0

3 years ago