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Nonamiya [84]
4 years ago
5

What are you doing when you’re making sound? A. Causing air molecules to vibrate. B Causing photons to travel. C Causing air pre

ssure to drop. D Causing electromagnetic waves to radiate.
Physics
1 answer:
Greeley [361]4 years ago
5 0

Answer: A

Causing air molecules to vibrate

Explanation:

Sound is made by vibrations. And it is an energy. When any object vibrates, it causes movement in the air particles. These particles bump into the particles close to them, which makes them vibrate too causing them to bump into more air particles. This movement, called sound waves, keeps going until they run out of energy.

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The gravitational potential energy of an object is equal to its weight multiplied by its
Elina [12.6K]

Answer:

Height above a surface

Explanation:

Gravitational potential energy is the energy which an object possesses due to its position above a surface.

It is also the amount of work a force has to do in order to bring an object from a particular position to a point of reference.

It is given mathematically as:

P. E. = m*g*h

where m = mass of the body

g = acceleration due to gravity

h = height above a surface

m*g represents the weight of the object.

Hence, Gravitational potential energy is the product of an object's weight and its height above a surface/reference point.

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The instantaneous speed of a particle moving along one straight line is v(t) = ate−6t, where the speed v is measured in meters p
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Answer:

v_max = (1/6)e^-1 a

Explanation:

You have the following equation for the instantaneous speed of a particle:

v(t)=ate^{-6t}   (1)

To find the expression for the maximum speed in terms of the acceleration "a", you first derivative v(t) respect to time t:

\frac{dv(t)}{dt}=\frac{d}{dt}[ate^{-6t}]=a[(1)e^{-6t}+t(e^{-6t}(-6))]  (2)

where you have use the derivative of a product.

Next, you equal the expression (2) to zero in order to calculate t:

a[(1)e^{-6t}-6te^{-6t}]=0\\\\1-6t=0\\\\t=\frac{1}{6}

For t = 1/6 you obtain the maximum speed.

Then, you replace that value of t in the expression (1):

v_{max}=a(\frac{1}{6})e^{-6(\frac{1}{6})}=\frac{e^{-1}}{6}a

hence, the maximum speed is v_max = ((1/6)e^-1)a

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