What is weight in Newton’s, of a 50.-kg person on earth
1 answer:
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Answer:
W=16.58J
Explanation:
initial information we have
work:
stretched distance:
from this, we can find the value of the constant of the spring k, with the equation for work in a spring:
substituting known values:
and clearing for k:
and now we want to know how much work is done when we stretch the spring a distance of 6.5cm from equilibrium, so now x is:
and using the same formula for work, with the value of k that we just found: