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Vesna [10]
3 years ago
12

A neutral comb brushes

Physics
1 answer:
Serjik [45]3 years ago
3 0
? What’s the question
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What are the ending materials produced from cell respiration
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Carbon dioxide and water :) hope this helped!
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2 years ago
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At a particular temperature, the speed of sound is 330 m/s and its frequency is 990 Hz. Choose the correct wavelength of this so
koban [17]

Answer:

1/3 M

I hope this helps :) sorry its late

8 0
3 years ago
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What force is needed to accelerate a 1,000-kilogram car from a stop to 5 m/s/s?
solong [7]
That depends on how soon you want it to reach 5 m/s/s. Without friction, ANY force will accelerate the car, like a mosquito pushing on it, but a Space Shuttle booster will accelerate it at a greater rate.
3 0
3 years ago
The speed of light in vacuum is defined to be c = 299,792,458 m/s = 1 μ0ε0 . The permeability constant of vacuum is defined to b
Radda [10]

Explanation:

It is given that,

The speed of light in vacuum is, c = 299,792,458 m/s

The permeability constant of vacuum is, \mu_o=4\pi\times 10^{-7}\ N.s^2/C^2

Let \epsilon_o is the permittivity of free space. The relation between \mu_o,\epsilon_o\ and\ c is given by :

c=\dfrac{1}{\sqrt{\mu_o\epsilon_o}}

\epsilon_o=\dfrac{1}{c^2u_o}

\epsilon_o=\dfrac{1}{(299792458\ m/s)^2\times 4\pi\times 10^{-7}\ N.s^2/C^2}

\epsilon_o=8.85\times 10^{-12}\ C^2/N.m^2

Hence, this is the required solution.

3 0
3 years ago
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An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavie
leva [86]

To solve the problem it is necessary to apply conservation of the moment and conservation of energy.

By conservation of the moment we know that

MV=mv

Where

M=Heavier mass

V = Velocity of heavier mass

m = lighter mass

v = velocity of lighter mass

That equation in function of the velocity of heavier mass is

V = \frac{mv}{M}

Also we have that m/M = 1/7 times

On the other hand we have from law of conservation of energy that

W_f = KE

Where,

W_f = Work made by friction

KE = Kinetic Force

Applying this equation in heavier object.

F_f*S = \frac{1}{2}MV^2

\mu M*g*S = \frac{1}{2}MV^2

\mu g*S = \frac{1}{2}( \frac{mv}{M})^2

\mu = \frac{1}{2} (\frac{1}{7}v)^2

\mu = \frac{1}{98}v^2

\mu = \frac{1}{g(98)(5.1)}v^2

Here we can apply the law of conservation of energy for light mass, then

\mu mgs = \frac{1}{2} mv^2

Replacing the value of \mu

\frac{1}{g(98)(5.1)}v^2  mgs = \frac{1}{2}mv^2

Deleting constants,

s= \frac{(98*5.1)}{2}

s = 249.9m

7 0
3 years ago
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