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3 years ago

A major process by which the Sun's energy is transported around the Earth system?

1 answer:

3 0

Is it Conduction. Here's my theory energy is transferred between the earth's surface and the atmosphere by Conduction, Convection and Radiation.

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A uranium and iron atom reside a distance R = 44.10 nm apart. The uranium atom is singly ionized; the iron atom is doubly ionize

Ad libitum [116K]

Answer:

distance r from the uranium atom is 18.27 nm

Explanation:

given data

uranium and iron atom distance R = 44.10 nm

uranium atom = singly ionized

iron atom = doubly ionized

to find out

distance r from the uranium atom

solution

we consider here that uranium electron at distance = r

and electron between uranium and iron so here

so we can say electron and iron distance = ( 44.10 - r ) nm

and we know single ionized uranium charge q2= 1.602 × $10^{-19}$ C

and charge on iron will be q3 = 2 × 1.602 × $10^{-19}$ C

so charge on electron is q1 = - 1.602 × $10^{-19}$ C

and we know F = $k\frac{q*q}{r^{2} }$

so now by equilibrium

Fu = Fi

$k\frac{q*q}{r^{2} }$ = $k\frac{q*q}{r^{2} }$

put here k = $9*10^{9}$ and find r

$9*10^{9}\frac{1.602 *10^{-19}*1.602 *10^{-19}}{r^{2} }$ = $9*10^{9}\frac{1.602 *10^{-19}*1.602 *10^{-19}}{(44.10-r)^{2} }$

$\frac{1}{r^{2} } = \frac{2}{(44.10 -r)^2}$

r = 18.27 nm

distance r from the uranium atom is 18.27 nm

6 0

3 years ago

Two carts, A and B, are connected by a spring and sitting at rest on a track. Cart A has a mass of 0.4 kg and Cart B has a mass

Ilya [14]

Both carts experience the same force but Cart A has a greater speed after the recoil.

The given parameters;

Mass of the cart A = 0.4 kg
Mass of the cart B = 0.8 kg

Apply the principle of conservation of linear momentum to determine the velocity of the carts after collision;

$m_Av_0_A\ + m_Bv_0_B = m_Av_f_A \ + m_Bv_f_B\\\\the \ initial \ velocity \ of \ both \ carts = 0\\\\0.4(0) + 0.8(0) = 0.4v_f_A + 0.8v_f_B\\\\0 = 0.4v_f_A + 0.8v_f_B\\\\0.4v_f_A = -0.8v_f_B\\\\v_f_A= \frac{-0.8 v_f_B}{0.4} \\\\v_f_A = - 2 \ v_f_B \ \ m/s$

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart A is equal to the force exerted on cart B but in opposite direction.

$F_A = -F_B$

Thus, the correct statement that compares the motion and forces acting on the two carts is "Both carts experience the same force but Cart A has a greater speed after the recoil."

Learn more about conservation of linear momentum here: brainly.com/question/7538238

6 0

2 years ago

true or false Newtons's First Law states "Acceleration depends on the mass of the object and the unbalanced force applied"

babunello [35]

False, his first law states: An object that's in motion will remain in motion at a constant velocity unless it's acted on by an unbalanced force.

8 0

3 years ago

Read 2 more answers

How long (in ns) does it take light to travel 1.0 m in vacuum?

Tema [17]

If light travels 290,000,000 meters in 1 second, simply divide 1 second by 290,000,000 to find the time it takes to travel 1 meter.

1 / 290,000,000 = 0.000000003448 seconds (or 3.5 nano seconds)

6 0

2 years ago

Two passengers are on a moving sidewalk at the airport. Passenger A is

Oksanka [162]

Answer:

V = - 2[m/s]

Explanation:

This is a classic problem of relative velocities, in order to solve it we must understand each of the velocities, given in the initial data of the problem.

VA = velocity of passenger A, = 1.5[km/h], it is the same velocity of the sidewalk

VB = 2 + 1.5 = 3.5 [km/h], that is the velocity observed by a person outside from the sidewalk.

And from the perspective of passenger B the speed of passanger A is:

VA-VB = - 2 [m/s]

It means that the passenger B is seen how passenger A is getting close to him and then passed.

8 0

3 years ago