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lyudmila [28]
3 years ago
13

Which period is the shortest in the long form of the periodic table? Name all the

Chemistry
1 answer:
Andreyy893 years ago
8 0

Answer:

The first period is the shortest in the long form of periodic table

Explanation:

the long form or the modern periodic table is based on ht modern periodic law. it has 7 periods and 18 groups. this periodic table is widely used by people all over the world. the chemical and physical properties of the elements can be easily identified due to their classification into groups and periods or their position in the periodic table. the first period is the shortest in the long form of periodic table. there are two elements present, they are- hydrogen(H) and helium (He)

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Oxygen has an electronegativity of 3.4, phosporus has an electronegativity of 2.2 The bond between them is
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B. polar covalent

Explanation:

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Slow cooling of hot magma leads to the formation of blank crystals<br> whats the blank
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Slow cooling of hot magma leads to the formation of large crystals
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How many oxygen molecules should be added to the reactants side to obey the law of conservation of matter?
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4 years ago
5) What is the difference between CO2 and XeCl2? The difference between SCl2, SCl4, and SCl6?
nadezda [96]

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(b)

SCl₆ is nonpolar because it has 6 bonding pairs and no lone pairs, giving it an octahedral shape. When you draw the vectors, you can see that the resultant is 0, making it nonpolar.

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7 0
3 years ago
C12H22O11 + 12O2 ---&gt; 12CO2 + 11H2O
boyakko [2]

Answer:

Oxygen is the limiting reactant.

Explanation:

Based on the reaction:

C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O

<em>1 mole of sucrose reacts with 12 moles of oxygen to produce 12 moles of CO₂ and 11 moles of H₂O.</em>

<em />

10.0g of sucrose (Molar mass: 342.3g /mol) are:

10.0g C₁₂H₂₂O₁₁ × (1mole / 342.3g) = 0.0292 moles of C₁₂H₂₂O₁₁

And moles of 10.0g of oxygen (Molar mass: 32g/mol) are:

10.0g O₂ × (1mole / 32g) = 0.3125 moles of O₂

For a complete reaction of 0.0292 moles of C₁₂H₂₂O₁₁ you need (knowing 12 moles of oxygen react per mole of sucrose):

0.0292 moles of C₁₂H₂₂O₁₁ × (12 moles O₂ / 1 mole C₁₂H₂₂O₁₁) = <em>0.3504 moles of O₂</em>

As you have just 0.3125 moles of O₂, <em>oxygen is the limiting reactant.</em>

8 0
4 years ago
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