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3 years ago

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Which period is the shortest in the long form of the periodic table? Name all the

1 answer:

Andreyy893 years ago

8 0

Answer:

The first period is the shortest in the long form of periodic table

Explanation:

the long form or the modern periodic table is based on ht modern periodic law. it has 7 periods and 18 groups. this periodic table is widely used by people all over the world. the chemical and physical properties of the elements can be easily identified due to their classification into groups and periods or their position in the periodic table. the first period is the shortest in the long form of periodic table. there are two elements present, they are- hydrogen(H) and helium (He)

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How many joules of energy are required to melt 423g of water at 0°C?

Mkey [24]

The amount of heat needed to melt 423 g of water at 0°C is 141282 J

The heat required to melt water can be obtained by using the following formula:

<h3>Q = mL </h3>

Q is the heat required.

L is the latent heat of fusion (334 J/g)

m is the mass.

With the above formula, we can obtain the heat required to melt the water as illustrated below:

Mass of water (m) = 423 g

Latent heat of fusion (L) = 334 J/g

<h3>Heat (Q) required =? </h3>

Q = mL

Q = 423 × 334

<h3>Q = 141282 J</h3>

Therefore, the amount of heat needed to melt 423 g of water at 0°C is 141282 J

Learn more: brainly.com/question/17084080

6 0

3 years ago

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The temperature of 75 mL of gas is decreased from 450 K to 150 K while the pressure is held constant. What is the new volume of

irinina [24]

Answer: Option A) 25mL

Explanation:

Given that,

Original volume of gas (V1) = 75mL

Original temperature of gas (T1) = 450K

New volume V2 = ?

New temperature T2 = 150K

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

75mL/450K = V2/150K

To get the value of T2, cross multiply

75mL x 150K = 450K x V2

11250mL•K = 450K•V2

Divide both sides by 450K

11250mL•K / 450K = 450K•V2/450K

25mL = V2

Thus, the new volume of the gas is 25mL

3 0

3 years ago

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The next 11 questions are related to the titration of 40.00 mL of a 0.0900 M acetic acid solution with 0.0700 M KOH. Assume that

liberstina [14]

Answer:

2.9 is the initial pH of the analyte solution.

Explanation:

The dissociation constant of acetic acid as per theoretical value = $K_a$

$K_a=10^{-4.756}=1.8\times 10^{-5}$

The initial concentration of acetic acid = c = 0.0900 M

$HAc\rightleftharpoons Ac^-+H^+$

initially

c 0 0

At equilibrium

(c-x) x x

The expression of dissociation constant :

$K_a=\frac{[Ac^-][H^+]}{[HAc]}$

$1.8\times 10^{-5}=\frac{x\times x}{(c-x)}$

$1.8\times 10^{-5}=\frac{x\times x}{(0.0900-x)}$

Solving for x:

x = 0.001264 M

$[H^+]=0.001264 M$

The pH of the solution :

$pH=-\log[0.001264]=2.898\approx 2.9$

2.9 is the initial pH of the analyte solution.

4 0

3 years ago

Super easy help me out

kupik [55]

The possibility for this answer would be E.

8 0

3 years ago

FREE 60 points & maybe one brain liest!!!!!!

Rudiy27

Answer:

THANKS SO MUCH

I actually did the same thin last week

Explanation:

4 0

3 years ago

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