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3 years ago

Formula for salt I will mark u brain list

Chemistry

1 answer:

Vesnalui [34]3 years ago

5 0

Answer:

The formula for salt is NaCl or Sodium chloride

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A loaf of bread has a volume of 700 cm3 and a mass of 420 g. what is the density of the bread?

joja [24]

We know that the equation for density is:

$D=\frac{m}{V}$

where D is the density, m is the mass in g, and V is the volume in either mL or cubic centimeters.

So then, given two of the variables, we can solve for density:

$D=\frac{420g}{700cm^{3}}$

$D=\frac{0.6g}{cm^{3}}$

Therefore, the density of the bread is 0.6g per cubic centimeter.

8 0

4 years ago

40.00 mL of 0.10 M KOH solution is titrated by 30.00 mL of 0.10 M HCl (adding HCl to KOH). What is the pH of the solution in the

Natali5045456 [20]

Answer:

$pH=12.16$

Explanation:

<u>The alkaline solution: </u>

40 ml of 0.1 M KOH

$n_{KOH}=\frac{1 L}{1000mL}*40mL*0.1M=0.004 mol$

<u>The acid solution: </u>

30 ml of 0.1 M HCl

$n_{HCl}=\frac{1 L}{1000mL}*30mL*0.1M=0.003 mol$

The neutralization reaction:

$HCl + KOH \longrightarrow KCl + H_2O$

For 1 mol of HCl, 1 mol of KOH is consumed. If 0.003 mol of HCl are added, 0.003 mol of KOH reacted.

After titration:

$n_{KOH}=0.001 mol$

$n_{HCl}= 0 mol$

Concentration (don't forget to add the volumes)

$n_{KOH}=\frac{1 1000mL}{1L *70mL}*0.001 mol=0.0143 mol$

Calcualtion of the pOH:

$pOH=-log([OH^-])=-log(0.0143)=1.84$

For the pH:

$pH=14-pOH=14-184=12.16$

4 0

3 years ago

Why are cells important?

victus00 [196]

They are the basic components of life or the basic building blocks of life

5 0

4 years ago

Read 2 more answers

When 943 J of heat is added to 10 grams of oil at 28˚C , the temperature increases to 89˚C. What is the specific heat of the oil

IgorLugansk [536]

Answer: 1.55 Jg°C

Explanation:

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 943 joules

Mass of oil = 10g

C = ? (let unknown value be Z)

Φ = (Final temperature - Initial temperature)

= 89°C - 28°C = 61°C

Then, Q = MCΦ

943 J = 10g x Z x 61°C

943J = 610g°C x Z

Z = (943J / 610g°C)

Z = 1.55 Jg°C

Thus, the specific heat of the oil is 1.55 Jg°C

7 0

4 years ago

The ionization constant of water at a temperature above 25°C is 1.7 x 10-14. What is the pH of pure water at this temperature?

lesya692 [45]

Answer:

The pH of pure water at this temperature is 6.88.

Explanation:

Ionization constant of water = $K_w=1.7 x 10^{-14}$

$2H_2O(l)\rightleftharpoons H_3O^+(aq) + OH^-(aq)$

Water will dissociate into equal amount of hydronium and hydroxide ions

$[H_3O^+] = [OH^-]= x$

$K_w=[H_3O^+]\times [OH^-]$

$K_w=1.7 x 10^{-14}=[H_3O^+]\times [OH^-]$

$1.7 x 10^{-14}=x^2$

$x=1.304\times 10^{-7}$

The pH of the solution is a negative logarithm of hydronium ions concentration.

The pH of pure water at this temperature:

$pH=-\log [H_3O^+]$

$pH=-\log (1.304\times 10^{-7})=6.88$

3 0

4 years ago

Formula for salt I will mark u brain list​

Formula for salt I will mark u brain list