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inessss [21]
4 years ago
10

Which statement best describes comparative and descriptive investigations?

Chemistry
2 answers:
sleet_krkn [62]4 years ago
8 0

Answer:

its the first one

Explanation:

scZoUnD [109]4 years ago
3 0

Answer:

They both include a question,procedure and conclusion.

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What are the steps through which a water particle travel as it made one complete trip through the water cycle?
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There are four main stages in the water cycle. They are evaporation, condensation, precipitation and collection. Let's look at each of these stages. Evaporation: This is when warmth from the sun causes water from oceans, lakes, streams, ice and soils to rise into the air and turn into water vapour (gas
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Does water diffuse faster in water or agar
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4 years ago
Large air masses moving across and area are called _____?
faltersainse [42]
Fronts. This includes cold fronts and warm fronts. Hoped this helped!
6 0
3 years ago
Read 2 more answers
20.00 mL of a 0.077 M solution of silver nitrate, AgNO3, is mixed with 30.00 mL of a 0.043 M solution of sodium acetate, NaC2H3O
babunello [35]

Answer:

No, no precipitate is formed.

Explanation:

Hello there!

In this case, since the reaction between silver nitrate and sodium acetate is:

AgNO_3(aq)+NaC_2H_3O_2(aq)\rightarrow AgC_2H_3O_2(s)+NaNO_3(aq)

In such a way, we can calculate the concentration of silver and acetate ions in the solution as shown below, and considering that the final total volume is 50.00 mL or 0.0500 L:

[Ag^+]=\frac{20.00mL*0.077M}{50.00mL}=0.0308M

[C_2H_3O_2^-]=\frac{30.00mL*0.043M}{50.00mL}=0.0258M

In such a way, we can calculate the precipitation quotient by:

Q=[Ag^+][C_2H_3O_2^-]=0.0308*0.0258=7.95x10^{-4}

Which is smaller than Ksp and meaning that the precipitation does not occur.

Regards!

3 0
3 years ago
2) The two solid blocks represented in the diagram are made of the same material and are under the same temperature and pressure
scoundrel [369]

Answer:

54 g

Explanation:

We'll begin by calculating the density of X. This can be obtained as follow:

Mass of X = 54 g

Length (L) = 9 cm

Breadth (B) = 2 cm

Height (H) = 1 cm

Volume of X = L × B × H

Volume of X = 9 × 2 × 1

Volume of X = 18 cm³

Density of X =?

Density = mass /volume

Density of X = 54/18

Density of X = 3 g/cm³

Finally, we shall determine the mass of Y as follow:

Length (L) = 3 cm

Breadth (B) = 3 cm

Height (H) = 2 cm

Volume of Y = L × B × H

Volume of Y = 3 × 3 × 2

Volume of Y = 18 cm³

Density of Y = Density of X (since they are made of the same material)

Density of X = 3 g/cm³

Density of Y = Density of X = 3 g/cm³

Mass of Y =.?

Density = mass /volume

3 = mass of Y /18

Cross multiply

Mass of Y = 3 × 18

Mass of Y = 54 g

5 0
3 years ago
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