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Irina-Kira [14]
3 years ago
10

How could I study for my science test on science inquiry?

Chemistry
1 answer:
Debora [2.8K]3 years ago
7 0

You could make flashcards. Or review previous lessons about the subject.

Hope this helped! :D

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Anthony made a pitfall trap by burying a small glass in the ground so that the top of the glass was exactly level with the groun
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Spiders and ground beetles.

Why is Anthony so mean? Don't hurt the beetles!

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3 years ago
2. How many moles of sodium Na will react with 6 moles of sulfur S?
fredd [130]

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12 moles of Na

Explanation:

5 0
2 years ago
What is the difference in concentration between a pH of 7 and 12?
Ratling [72]

Answer:

The pH of a solution is simply a measure of the concentration of hydrogen ions,  

H

+

, which you'll often see referred to as hydronium cations,  

H

3

O

+

.

More specifically, the pH of the solution is calculated using the negative log base  

10

of the concentration of the hydronium cations.

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

pH

=

−

log

(

[

H

3

O

+

]

)

a

a

∣

∣

−−−−−−−−−−−−−−−−−−−−−−−−  

Now, we use the negative log base  

10

because the concentration of hydronium cations is usually significantly smaller than  

1

.

As you know, every increase in the value of a log function corresponds to one order of magnitude.

Explanation:

4 0
3 years ago
Read 2 more answers
Which of the following are parts of the excretory system? *
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Answer:

kidney, bladder, rectum, urethera

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5 0
3 years ago
Determine the root-mean square speed of CO2 molecules that have an average kinetic energy of 4.2 x10-21 J per molecule.
strojnjashka [21]
<span>Determine the root-mean-square sped of CO2 molecules that have an average Kinetic Energy of 4.21x10^-21 J per molecule. Write your answer to 3 sig figs.
</span><span>
E = 1/2 m v^2 

If you substitute into this formula, you will get out the root-mean-square speed. 

If energy is Joules, the mass should be in kg, and the speed will be in m/s. 

1 mol of CO2 is 44.0 g, or 4.40 x 10^1 g or 4.40 x 10^-2 kg. 

If you divide this by Avagadro's constant, you will get the average mass of a CO2 molecule. 

4.40 x 10^-2 kg / 6.02 x 10^23 = 7.31 x 10^-26 kg 

So, if E = 1/2 mv^2 

</span>v^2 = 2E/m = 2 (4.21x10^-21 J)/7.31 x 10^-26 kg = 115184.68 
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8 0
3 years ago
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