Question

Solve for x? and the lengths missing side

Answer 1

Answer:

X = 15, the missing length (c) is 10

Step-by-step explanation:

Using Pythagorean’s Theorem we know that a^2 + b^2 = c^2

We have side a and b, represent a as 6 and b as 8.

We have 6^2 + 8^2 = c^2

Which equals 100 = c^2

10 = c

Side C is 10, and (x - 5) = 10

X = 15

Please mark BRAINLIEST!

Answer 2

Answer: x ≅ 15.95

Step-by-step explanation:

Use the pythagorean theorem for right triangles x^2 + y^2 = s^2

6^2 = 36

8^2 = 64

(x - 5)^2 requires FOIL. Unfortunately Im going to do this on paper. Its essentially First Outside Inside Last. i got x^2 - 10x + 25

Lets now add 36 and 84 and make it equal to the trinomial we just got.

$120=x^2-10x+25$

Now lets subtract 120 from both sides to get:

$0=x^2-10x-95$

You could complete the square, I think. But im going to use the quadratic formula. $\frac{-b +/- \sqrt{b^2-4ac} }{2a}$Im going to calculate this on paper for simplicity's sake. Im getting an answer of about $\frac{10(+/-)21.909}{2}$

Solve by adding and then solve by subtracting to get x ≅ 15.95 and x = -5.95. We cant have a negative side length so we can disregard that negative answer.