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vivado [14]
3 years ago
6

What is the interquartile range of the data ? 0,2,4,0,2,3,8,6

Mathematics
1 answer:
Alexeev081 [22]3 years ago
6 0

(arrange the data set from least to greatest)

0, 0, 2, 2, 3, 4, 6, 8

(find the median: *the middle number*)

Median: 2.5

Lower quartile: 1

Upper quartile: 5

Interquartile range : upper quartile - lower quartile = answer

Interquartile range: 5 - 1 = 4

So the IQR or interquartile for the following data set is 4.

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Method 1:

Look at the picture.

\dfrac{1}{7} is greater than \dfrac{1}{9}

\boxed{\dfrac{1}{7}>\dfrac{1}{9}}

Method 2:

Find the common denominator:

multiples of 7: 0, 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, ...

multiples of 9: 0, 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, ...

63 = 7 · 9

\dfrac{1}{7}=\dfrac{1\cdot9}{7\cdot9}=\dfrac{9}{63}\\\\\dfrac{1}{9}=\dfrac{1\cdot7}{9\cdot7}=\dfrac{7}{63}

\dfrac{9}{63} > \dfrac{7}{63}

therefore

\dfrac{1}{7} > \dfrac{1}{9}

3 0
3 years ago
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Bumek [7]

Answer:

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Step-by-step explanation:

Given that:

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Cost of a 12 miles ride for taxi 1 and taxi 2.

Solution:

Let us first convert the charges of each taxi to per mile.

Taxi 1 charges are already given in per mile.

Charges for 1 mile = $3

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Taxi 2 charges = 1.77 \times 1.61 = $2.85 per mile

Charges for 12 miles = 2.85 \times 12 = <em>$34.20</em>

<em></em>

Therefore, the answer is:

<em>A 12 mile ride in Taxi 1 costs $36.00, and in Taxi 2 it costs $34.20.</em>

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Answer:

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Step-by-step explanation:

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sergiy2304 [10]
The third option is quadratic

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WITCHER [35]

Answer:

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3 years ago
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