The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
Answer: the answer is x<-4 so the correct answer choice would be D
Step-by-step explanation: Hope this helps :)
Answer:
9/8
Step-by-step explanation:
time A / time B = (3/2)/(4/3) = (3/2)(3/4) = (3·3)/(4·2)
time A / time B = 9/8
Answer:
x=5
Step-by-step explanation:
The sum of the angles of a quadrilateral is 360
L+M+J+K =360
75+ 96+14x+5 +114 = 360
Combine like terms
290 +14x = 360
Subtract 290 from each side
290-290 +14x= 360-290
14x = 70
Divide by 14
14x/14 = 70/14
x = 5
