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polet [3.4K]
3 years ago
8

Find the slope of a line that is perpendicular to the line containing the points [-2,-1] and [2,-3]. How did you find it?

Mathematics
1 answer:
xxMikexx [17]3 years ago
8 0
A line perpendicular to another will have the opposite sign and be flipped

ex: slope is 4/5 the other lines slope will be -5/4

(-2,-1) (2,-3)

slope formula

y2-y1/x2-x1

-3-(-1)
____
2-(-2)

-3+1
___
2+2

-2
___
0

the slope of the perpendicular line is 0/-2 which is just 0
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Now solve for y'.

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Now you will have to clear y, with the square root.

[tex]y'^{\frac{2}{2}} = \sqrt{x + 4}  / \sqrt{9}[/tex] =

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You can check the answer by doing the evaluation of the following equation:

(f o f^{-1} ) (x)

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