Find the slope of a line that is perpendicular to the line containing the points [-2,-1] and [2,-3]. How did you find it?

1 answer:

8 0

A line perpendicular to another will have the opposite sign and be flipped

ex: slope is 4/5 the other lines slope will be -5/4

(-2,-1) (2,-3)

slope formula

y2-y1/x2-x1

-3-(-1)
____
2-(-2)

-3+1
___
2+2

-2
___
0

the slope of the perpendicular line is 0/-2 which is just 0

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Step-by-step explanation:

$m \angle \: 5 + m \angle \:6 = 180 \degree \\ (straight \: line \: \angle s) \\ \therefore \: (2x)\degree + 48\degree = 180 \degree \\ \therefore \: (2x)\degree = 180 \degree - 48\degree\\ \therefore \: (2x)\degree = 132 \degree \\ \therefore \:x = \frac{132}{2} \\ \: \: \: \huge \purple{ \boxed{\therefore \:x = 66}}$