Answer:
5.9x10^-2 M
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Concentration of CO, [CO] = 0.30 M
Concentration of H2, [H2] = 0.10 M
Concentration of H2O, [H2O] = 0.020 M
Equilibrium constant, K = 3.90
Concentration of CH4, [CH4] =..?
Step 2:
The balanced equation for the reaction. This is given below:
CO(g) + 3H2(g) <=> CH4(g) + H2O(g)
Step 3:
Determination of the concentration of CH4.
The expression for equilibrium constant of the above equation is given below:
K = [CH4] [H2O] / [CO] [H2]^3
3.9 = [CH4] x 0.02/ 0.3 x (0.1)^3
Cross multiply to express in linear form
[CH4] x 0.02= 3.9 x 0.3 x (0.1)^3
Divide both side by 0.02
[CH4] = 3.9 x 0.3 x (0.1)^3 /0.02
[CH4] = 5.9x10^-2 M
Therefore, the equilibrium concentration of CH4 is 5.9x10^-2 M
