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kumpel [21]
3 years ago
9

A chemist requires 0.752 mol na2co3 for a reaction. how many grams does this correspond to?

Chemistry
1 answer:
Sliva [168]3 years ago
8 0
<span>79.70 grams First, calculate the molar mass of Na2CO3 by looking up the molar mass of the elements used in it. Sodium = 22.989769 Carbon = 12.0107 Oxygen = 15.999 Multiply each molar mass by the number of atoms used, and sum the results to get the molar mass 2 * 22.989769 + 12.0107 + 3 * 15.999 =105.9872 Finally, multiply the molar mass by the number of moles you need. 0.752 * 105.9872 = 79.7024 grams</span>
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Answer:

\large \boxed{\text{6.0 mL} }

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

p_{1}V_{1} = p_{2}V_{2}

Data:

\begin{array}{rcrrcl}p_{1}& =& \text{500 mmHg}\qquad & V_{1} &= & \text{9.0 mL} \\p_{2}& =& \text{750 mmHg}\qquad & V_{2} &= & ?\\\end{array}

Calculations:  

\begin{array}{rcl}500 \times 9.0 & =& 750V_{2}\\4500 & = & 750V_{2}\\V_{2} & = &\dfrac{4500}{750}\\\\& = & \textbf{6.0 mL}\\\end{array}\\\text{The volume of the gas is } \large \boxed{\textbf{6.0 mL}}

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<h3>What is the effect of concentration on equilibrium?</h3>

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<h3>Factors affecting the concentration of the reaction</h3>
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brainly.com/question/12252562

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Answer:

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