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kondor19780726 [428]
3 years ago
10

I need help on edge

Physics
1 answer:
maks197457 [2]3 years ago
8 0
It is wave front
That’s the answer
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What is the kinetic energy of a 145 g baseball moving at 42 m/s?
klio [65]
Answer:
Kinetic energy = 127.89 Joules

Explanation:
Kinetic energy is calculated using the following rule:
KE = (1/2)*v* v^2
Where:
m is the mass = 145 g = 0.145 kg
v is the velocity = 42 m/sec

Substitute in the above equation to get the kinetic energy as follows:
KE = (0.5)(0.145)(42)^2
Kinetic energy = 127.89 Joules

Hope this helps :)
8 0
4 years ago
EXPLAIN CONSERVATION OF MOMEMTUM WITH THE HELP OF COLLISION OF TWO OBJECT.
Vlada [557]

i hate this question.

Conservation of momentum - is when the total momentum before and after collision is equal.

Here is the formula darling,

p = p

mv = mv

See the pic for example. HmpH

6 0
3 years ago
What is the speed of sound dependent on?
mojhsa [17]
Depends on the elasticity and density of the medium through what it is traveling <span> </span>
5 0
3 years ago
The brain is responsible for storing memories. How is this helpful for helping the body react to stimuli? ANSWER PLEASEEE​
Murljashka [212]

Answer:

Memories occur when specific groups of neurons are reactivated. In the brain, any stimulus results in a particular pattern of neuronal activity—certain neurons become active in more or less a particular sequence. ... Memories are stored by changing the connections between neurons. When the memories are stored, the stimuli can be recalled by being remembered. Explanation:

Hope it helps, I'm not 100% sure it's right though.

7 0
3 years ago
An green hoop with mass mh = 2.8 kg and radius rh = 0.17 m hangs from a string that goes over a blue solid disk pulley with mass
vladimir2022 [97]
The mass of the hoop is the only force which is computed by:F net = 2.8kg*9.81m/s^2 = 27.468 N 
the slow masses that must be quicker are the pulley, ring, and the rolling sphere. 
The mass correspondent of M the pulley is computed by torque τ = F*R = I*α = I*a/R F = M*a = I*a/R^2 --> M = I/R^2 = 21/2*m*R^2/R^2 = 1/2*m 
The mass equal of the rolling sphere is computed by: the sphere revolves around the contact point with the table. So using the proposition of parallel axes, the moment of inertia of the sphere is I = 2/5*mR^2 for spin about the midpoint of mass + mR^2 for the distance of the axis of rotation from the center of mass of the sphere. I = 7/5*mR^2 M = 7/5*m 
the acceleration is then a = F/m = 27.468/(2.8 + 1/2*2 + 7/5*4) = 27.468/9.4 = 2.922 m/s^2
6 0
3 years ago
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